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Natasha2012 [34]
3 years ago
13

PLEASEEEEEEEEE HELP I AM FAILING :(((

Mathematics
2 answers:
mylen [45]3 years ago
5 0

Answer:

Step-by-step explanation:

8) Here y becomes 16y. Hence there is a vertical compression

D)

12) horizontal shift of 87 units to the right

13) since for x <-1 f(x) = [x] we have

f(-2)=-2 since -2 is the greatest integer contained in itself.

Option C

18) if it is 1/(x+3) then 3 units to left.

IRISSAK [1]3 years ago
4 0
8 (D)
12(C) (Considering it is (square root of x) - 87, and not square root of (x-87).)
18(C) (Again, same as above. You need to write in parentheses, if applicable.)
13 I can't understand the question. Am I missing an equation?
Best answer me please.
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P is a prime number and q is a positive integers such that p + q = 1696 IF P and Q are co primes and their Lcm is 21879 Then fin
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Answer:

P = 1 3  

Q = 1 6 8 3

Step-by-step explanation:

through factorization of 21879

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3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
4 years ago
Irrational numbers can never be precisely represented in decimal form, why is this?
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3 0
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Harper plans to purchase her school pictures. The prints cost $108 plus any add-ons she wants to purchase. If she saves $18 per
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Answer:

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Step-by-step explanation:

Weeks = x

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X = $108/$18

X = 6

So 6 weeks

4 0
3 years ago
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