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2 years ago

11

michelle has a starting balance on a gift card a for $300. She buys several dresses for $40 a piece. After her purchase she has

$140 left on the gift card. How many dresses did she buy?

2 answers:

anyanavicka [17]2 years ago

5 0

She had to of bought 4 dresses if they each equal $40

Olenka [21]2 years ago

4 0

$300 - $140 = $160

Now we do $160 divided by $40

That means she bought 4 dresses for $40 dollars each

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If $190 is invested at an interest rate of 11% per year and is compounded continuously, how much will the investment be worth in

dangina [55]

Answer:

$295.01

Step-by-step explanation:

Using the compounding continuously formula, we are looking for A. We have that P = 190; r = .11 (always use the decimal form of the rate!); and t = 4. Filling in we have:

$A=190e^{(.11)(4)}$

Simplifying that multiplication:

$A=190e^{.44}$ .

On your calculator, raise e to the .44 power to get

A = 190(1.552707219) and

A = $295.01

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3 years ago

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scoundrel [369]

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2 years ago

Read 2 more answers

The internet was used by 30% of the population of a state in 2008. If 3200 people were surveyed, how many in the survey were usi

andrew-mc [135]

1. We know that 30% expressed as a decimal is 0.30

Since 30% of people were using the internet, 0.30*3200 is our answer.
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3 years ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$

$\Rightarrow x =(50 \times 14)/57=12.28$ grams

and $y = 14-x= 14-12.28=1.72$ grams.

Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.

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2 years ago