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r-ruslan [8.4K]
3 years ago
8

Evaluate: 542 × 31

Mathematics
1 answer:
ryzh [129]3 years ago
5 0

Answer:

<h2>C. 16,802</h2>

Step-by-step explanation:

h h h h h h h h h h

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given that 8-sqrt(18) over sqrt(2) = a + b sqrt(2) where a and b are integers find the value of a and b
Novay_Z [31]

Answer:

a = - 3 and b = 4

Step-by-step explanation:

Given

\frac{8-\sqrt{18} }{\sqrt{2} }

Simplify \sqrt{18}

= \sqrt{9(2)} = \sqrt{9} × \sqrt{2} = 3\sqrt{2}

Thus expression can be written as

\frac{8-3\sqrt{2} }{\sqrt{2} }

Multiply numerator/denominator by \sqrt{2}

noting that \sqrt{2} × \sqrt{2} = 2

= \frac{\sqrt{2}(8-3\sqrt{2})  }{\sqrt{2}(\sqrt{2})  }

= \frac{8\sqrt{2}-6 }{2}

Dividing each term on the numerator by 2

= 4\sqrt{2} - 3

= - 3 + 4\sqrt{2}

with a = - 3 and b = 4

6 0
3 years ago
Read 2 more answers
Find the slope of the line graphed below.
Dima020 [189]

Answer:

y=1.5x-8

Step-by-step explanation:

this is because you first need to fond the change in the x axis and the y axis which will give you the gradient. Then you will have to substitute any co-ordinate and gives you c.(Y=mx+c) is the equation of a straight line.

5 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
Jason compares the price of oranges at 4 stores,
prisoha [69]

Answer/Step-by-step explanation:

To Find the best price divided each

Kroger → 1.52/4=0.38

Publix → 175/5=35

Ingles → 1.02/3=0.34

Walmart → 2.46/6=0.41

Base on the data we can tell that Ingles have the best price.

7 0
2 years ago
NO LINKS PLEASE I ACTUALLY NEED HELP THEY'RE 2 PARTS
eimsori [14]
I’m on the same question
3 0
3 years ago
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