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r-ruslan [8.4K]
3 years ago
8

Evaluate: 542 × 31

Mathematics
1 answer:
ryzh [129]3 years ago
5 0

Answer:

<h2>C. 16,802</h2>

Step-by-step explanation:

h h h h h h h h h h

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David drops a ball from a bridge at an initial height of 100 meters.
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The general formula is:
y = y_{o} + v_{o}t -  \frac{1*g*t^{2} }{2} -- (A)

Where g = 9.8 m/s/s
v_{o} = 0
y_{o} = 100

a)
Time=t=3s.
Plug-in the values in (A)
y = 100 -(1/2*9.8*3*3)
y = 100-44.1 = 55.9m

Height of the ball exactly after 3 seconds = 55.9m.

b)
At ground, y=0; Plug-in values in (A):
A=> 0 = 100 - (1/2* 9.8 * [tex]t_{2}[/text])
Therefore t = + 4.52 s and - 4.52 seconds.

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Klio2033 [76]

Answer: 5^2

Step-by-step explanation:

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To solve 493x = 3432x+1, write each side of the equation in terms of base
sleet_krkn [62]

<u><em>Answer</em></u>

= 3.405 × 10⁻⁴

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If the question is correctly written, then it is very easy.

First, take the like terms on one side.

493x = 3432x+1

493x - 3432x = 1

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Dividing both sides by -2939 to get the value of x.

x = 1/(-2939)

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= 3.405 × 10⁻⁴

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