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Rudiy27
3 years ago
9

When supply and demand for a product increase simultaneously, we can predict that both the market clearing price and the equilib

rium quantity will increase. cannot predict the market clearing price, but know that the equilibrium quantity will increase. can predict that both the market clearing price and the equilibrium quantity will decrease. cannot predict the change in either the equilibrium quantity or the market clearing price.
Chemistry
1 answer:
Whitepunk [10]3 years ago
3 0

Answer: Explanation:

When supply and demand for a product increase simultaneously, we cannot predict the market clearing price, but know that the equilibrium quantity will increase.

NB: We cannot predict the market clearing price because no adequate information such as government policy is provided. such information would likely affect the market clearing price either positively or negatively.

P.S: This is a business question.

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Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 40 mm Hg. Assume hemoglobin is 50%% sa
kumpel [21]

Answer:

The fractional saturation for hemoglobin is 0.86

Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Where Y_{O_{2} } \\ is the fractional oxygen saturation

{P_{O_{2} } is the partial pressure of oxygen

P_{50} is the partial pressure when 50% hemoglobin is saturated with oxygen

and h is the Hill coefficient

From the question,

{P_{O_{2} } = 40 mm Hg

P_{50} = 22 mm Hg

h = 3

Putting these values into the equation, we get

Y_{O_{2} } = \frac{(P_{O_{2} })^{h}  } {(P_{50})^{h}  + (P_{O_{2} })^{h}   }

Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3}  }

Y_{O_{2} } = \frac{64000 }{10648 + 64000  }

Y_{O_{2} } = \frac{64000 }{74648 }

Y_{O_{2} } = 0.86

Hence, the fractional saturation for hemoglobin is 0.86.

4 0
3 years ago
Name the compound containing only fluorine and hydrogen.
Sonbull [250]
Hydrogen has only one electron. It has one proton of nucleus and one outter electron.
7 0
3 years ago
What is the ratio of the concentration of sodium acetate to the concentration of acetic acid at ph 5.75?
GREYUIT [131]
To get the ratio of the concentration of sodium acetate to the concentration of acetic acid we are going to use H-H equation:

when:

PH = Pka + ㏒[salt/acid]

when the Ka of acetic acid = 1.75 x 10^-5 

so, we can get Pka from this formula:

Pka = -㏒Ka

       = -㏒1.75 x 10^-5

      = 4.76

and when we have PH = 5.75, so by substitution:

∴ 5.75 = 4.76 + ㏒[acetate/ acetic acid]

∴ [acetate/acetic acid] = 9.77

∴ the ratio of a concentration of acetate to acetic acid 9.77

4 0
3 years ago
If the diver were to ascend to the surface (where the pressure is 1.0 atm) while holding her breath, to what volume would the ai
sertanlavr [38]

Im not 100% sure put i think 6.0

5 0
4 years ago
A helium balloon has a pressure of 0.2 kPa and a volume of 15 L. If the pressure increases to 0.5 kPa, what volume will the ball
Alex17521 [72]

Answer:

6.0 L

Explanation:

For this question, we can use

P1×V1= P2 × V2

where

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V1 (initial volume)= 15L

P2 (final pressure)= 0.5 kPa

V2(final volume)= ?

Since we are trying to find final volume, we can rearrange the equation to make V2 the subject.

V2= (P1 × V1)/ P2

V2= (0.2 ×15)/0.5

V2 =6 L

7 0
3 years ago
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