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Rudiy27
3 years ago
9

When supply and demand for a product increase simultaneously, we can predict that both the market clearing price and the equilib

rium quantity will increase. cannot predict the market clearing price, but know that the equilibrium quantity will increase. can predict that both the market clearing price and the equilibrium quantity will decrease. cannot predict the change in either the equilibrium quantity or the market clearing price.
Chemistry
1 answer:
Whitepunk [10]3 years ago
3 0

Answer: Explanation:

When supply and demand for a product increase simultaneously, we cannot predict the market clearing price, but know that the equilibrium quantity will increase.

NB: We cannot predict the market clearing price because no adequate information such as government policy is provided. such information would likely affect the market clearing price either positively or negatively.

P.S: This is a business question.

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HELP ASAP 20 POINTS
Colt1911 [192]

Solubility of a compound in water can be referred to as the amount of the compound that can be dissolved in 1 L of the solvent (water) at any given temperature. Solubility of a compound can be expressed in the units of g/L or mg/L.

Given that the solubility of calcium carbonate in water = 14 mg/L

We have to calculate the volume of water that can dissolve 11 g of calcium carbonate.

Converting 11 g calcium carbonate to mg:

11g *\frac{1000mg}{1g} =11,000 mg

Volume of water that would dissolve 11000 mg calcium carbonate

                             = 11000 mg CaCO_{3}*\frac{1L}{14 mg}

                             =785.7 L

Rounding the volume 785.7 L to two significant figures, we get 790 L water.

Therefore, we would need 790 L water to completely dissolve 11 g of calcium carbonate.

4 0
3 years ago
Consider this reaction mechanism:
tester [92]

Answer:

c)Mo(CO)6 + P(CH3)3  Mo(CO)5P(CH3)3 + CO

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8 0
3 years ago
At 35°C, K = 1.6 × 10^-5 for the reaction
TEA [102]

Answer:

a) [NOCl] = 0.968 M

[NO] = 0.032M

[Cl²] = 0.016M

b) [NOCl] = 1.992M

[NO] = 0.008 M

[Cl2]  = 1.004 M

Explanation:

Step 1: Data given

Temperature = 35°C = 308K

K = 1.6 × 10^-5

Step 2: The reaction

2 NOCl(g) ⇌ 2 NO(g) + Cl2(g)

For 2 moles NOCl we'll have 2 moles NO and 1 mol Cl2

Step 3

a. 2.0 mol pure NOCl in a 2.0 L flask

Concentration at the start:

Concentration = mol / volume

[NOCl] = mol / volume

[NOCl] = 2.0 / 2.0 L

[NOCl] = 1.0 M

[NO] = 0 M

[Cl] = 0M

Concentration at the equillibrium

[NOCl] = 1.0M - 2x

[NO] = 2x

[Cl2]= x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6*10^-5 = ((2x)² * x) / (1.0-2x)²

x = 0.016

[NOCl] = 1.0 -  2*0.016 = 0.968 M

[NO] = 2*0.016 = 0.032M

[Cl²] = 0.016M

b. 2.0 mol NOCl and 1.0 mol Cl2 in a 1.0 L flask

Concentration at the equillibrium

[NOCl] = 2.0 mol / 1.0 L = 2.0 M

[NO] = 0 M

[Cl2]= 1.0 mol / 1.0 L = 1.0 M

Concentration at the equillibrium

[NOCl] = 2.0M - 2x

[NO] = 2x

[Cl2]= 1.0 + x

K = [Cl2][NO]² / [NOCl]² = 1.6*10^-5

1.6 *10^-5 = (2x)²*(1.0+x) / ((2.0-2x)²)

1.6 *10^-5= (2x)² * 1 )/2.0²

1.6 *10^-5= 4x² / 4 = x²

x = \sqrt{1.6 *10^-5} = 4.0*10^-3

[NOCl] = 2.0 - 2*0.004 = 1.992M

[NO] = 2*0.004 = 0.008 M

[Cl2] = 1+ 0.004M = 1.004 M

5 0
3 years ago
What is percent of C in CO2 (C=12.01 amu, O=16.00 amu)
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Answer: 33%

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