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yulyashka [42]
3 years ago
9

Help me show work please

Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - given point

\bullet\ (2,\ 7),\ m=-4\\\\y-7=-4(x-2)\\\\\bullet(-6,\ -2),\ m=3\\\\y-(-2)=3(x-(-6))\to y+2=3(x+6)\\\\\bullet(12,\ 5),\ m=-3\\\\y-5=-3(x-12)\\\\\bullet(7,\ -6),\ m=\dfrac{1}{2}\\\\y-(-6)=\dfrac{1}{2}(x-7)\to y+6=\dfrac{1}{2}(x-7)\\\\\bullet(4,\ -5),\ m=6\\\\y-(-5)=6(x-4)\to y=y+5=6(x-4)\\\\\bullet(-8,\ 2),\ m=-\dfrac{3}{4}\\\\y-2=-\dfrac{3}{4}(x-(-8))\to y-2=-\dfrac{3}{4}(x+8)

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~ Simplifying

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(10 + -14x) = -14x + 10

~ Reorder the terms:

10 + -14x = 10 + -14x

~ Add '-10' to each side of the equation.

10 + -10 + -14x = 10 + -10 + -14x

~ Combine like terms: 10 + -10 = 0

0 + -14x = 10 + -10 + -14x

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~ Combine like terms: 10 + -10 = 0

-14x = 0 + -14x

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~ Add '14x' to each side of the equation.

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0 = -14x + 14x

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Answer:

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Step-by-step explanation:

Considering 'y' be the number

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As 'y' is equal to twice a smaller number plus 3.

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solving

\begin{bmatrix}y=2x+3\\ y=2x+1\end{bmatrix}

\mathrm{Subsititute\:}y=2x+1

\begin{bmatrix}2x+1=2x+3\end{bmatrix}

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