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2 years ago

5

Here is a polygon on a grid. An L shaped figure on a square grid. Draw a scaled copy of this polygon that has a perimeter of 30

units. What is the scale factor? Explain how you know.

1 answer:

yanalaym [24]2 years ago

6 0

Answer: the perimeter of this L shaped figure is 10 units, so scaling it by 3× would make the perimeter 30 units. so the scale factor is 3

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The vertex form of the equation of a parabola is y= 3(x - 4)^2 -22. What is the standard form of the equation

Sunny_sXe [5.5K]

Answer:

option A

Step-by-step explanation:

We can find the standard form by expanding the equation:

y = 3(x-4)^2 - 22

y = 3(x^2 - 8x + 16) - 22

y = 3x^2 - 24x + 48 - 22

y= 3x^2 - 24x + 26

So the correct option is option A

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2 years ago

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Find the general solution of {y}''-3y=8e^{3t}+4sin(t) .

babunello [35]

Answer:

$y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint$

Step-by-step explanation:

We are given that linear differential equation

$y''-3y=8e^{3t}+4 sint$

Auxillary equation

$D^2-3=0$

$D=\pm \sqrt3$

C.F= $C_1e^{\sqrt3t}+C_2e^{-\sqrt3}$

P.I= $\frac{8e^{3t}+4sin t}{D^2-3}$

P.I= $\frac{8e^{3t}}{9-3}+4\frac{sint }{-1-3}$

P.I= $e^{ax}{\phi (D+a)}$ and $P.I=\frac{sinax}{(\phi D)}$ where D square is replace by - a square

P.I= $-\frac{4}{3}e^{3t}- sint$

Hence, the general solution

G.S=C.F+P.I

$y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint$

3 0

2 years ago

Solve:<br> I kept trying but I can’t do it <br> Thank you a lot for you help

scoray [572]

Answer:

5.25

Step-by-step explanation:

15/10=1.5

9*1.5=13.5

13.5-3=10.5

10.5/2=5.25

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2 years ago

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Helpppppppppppp.!!!!!!!!!!!!

elena55 [62]

Yes both rates are equivalent

6 0

3 years ago

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3 2/9 + 1 1/3 write in simplest form

Ratling [72]

Answer: 41/9 or 4 5/9

Step-by-step explanation:

3 2/9 = 29/9

1 1/3 = 4/3

4(3)/3(3) + 29/9

12/9+29/9 = 41/9

41/9 can be also written as 4 5/9

7 0

2 years ago