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Pavel [41]
1 year ago
8

2 lines 3y-2x=21 and 4y+5x=5, intersect at the point Q. Find the coordinates of Q

Mathematics
1 answer:
erik [133]1 year ago
7 0

Answer: (-3,5)

Step-by-Step Solution:

1. Set 1 equation equal to y

3y-2x=21

3y=2x+21

y=2/3x+7

2. Set the other equation equal to y

4y+5x=5

4y=-5x+5

y=-5/4x+5/4

3. Set the equations equal to each other, and solve for x

2/3x+7=-5/4x+5/4

2/3x+23/4=-5/4x

(Multiply by 12 on both sides to get rid of fractions)

8x+69=-15x

8x=-15x-69

23x=-69

x=-3

4. Solve for y

(Choose any of the equations)

y=2/3x+7

y=2/3(-3)+7

y=-2+7

y=5

ANSWER: (-3,5)

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Please help ❗️❗️❗️❗️ Please! I will reward brainly
zhuklara [117]
Hey there :)

We know the distance formula is:
D = \sqrt{(x2-x1)^2+(y2-y1)^2}

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
                                    ↓   ↓       ↓    ↓
                                    x₁ y₁     x₂   y₂
We plug in the values 
D =\sqrt{(8 -(-10))^2+(5-(-5))^2}
    ≈20.59 ≈ 20.6 (nearest tenth)

We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D = \sqrt{(-2-10)^2+(1-0)^2}
   ≈ 12.04 ≈ 12.0 (nearest tenth)

3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D = \sqrt{((7-4)^2+(-8-8)^2}
   ≈ 16.27 ≈ 16.3 (nearest tenth)

4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D = \sqrt{(8-(-10))^2+(8-(-4))^2}
    ≈ 21.6 (nearest tenth)

5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = \sqrt{(-8-6)^2 + (9-(-3))^2}
   ≈ 18.4 (nearest tenth) 

You can find the matching below :)



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