How do you write 2= -2/7x + y in slope-intercept form?

Mathematics

1 answer:

Scrat [10]3 years ago

5 0

You'll want to get y alone

y = -2/7x - 2

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As per the reference document attached thereby along with the question statement, if (∠SOX = 160°), [∠1 = (x + 14)], and [∠2 = (3x – 10)], then the measure of ∠2 in degrees will be 113°

As per the reference document attached thereby along with the question statement, (∠SOX = 160°), and it's constituent angles

[∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)],

And we are required to determine the measure of ∠2.

Since, [(∠SOW + ∠WOX) = ∠SOX],

Therefore, [{(x + 14) + (3x – 10)} = 160°]

Or, [{(x + 3x) + (14 - 10)} = 160°]

Or, [(4x - 4) = 160°]

Or, [4x = (160 + 4)°]

Or, (4x = 164°)

Or, [x = (164/4)°]

Or, (x = 41°)

Or, [(3x – 10) = {(3 * 41) - 10}°]

Or, [∠2 = (123 - 10)°]

Or, (∠2 = 113°)

That is, if (∠SOX = 160°), and it's constituent angles (∠1) and (∠2) measure as [∠1 = ∠SOW = (x + 14)], and [∠2 = ∠WOX = (3x – 10)], then the measure of ∠2 in degrees will be 113°

To learn more about Measures in Degrees, click on the link below.

brainly.com/question/12362603

#SPJ1

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Write the equation in slope-intercept form then change it to standard form with integer coefficients.

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