N=1→f(n)=f(1)=-5.25 (First term)
f(n)=f(n-1)+1.75, for n=2, 3, 4, ...
Second term:
n=2→f(2)=f(2-1)+1.75=f(1)+1.75=-5.25+1.75→f(2)=-3.5
Third term:
n=3→f(3)=f(3-1)+1.75=f(2)+1.75=-3.5+1.75→f(3)=-1.75
Fourth term:
n=4→f(4)=f(4-1)+1.75=f(3)+1.75=-1.75+1.75→f(4)=0
Fifth term:
n=5→f(5)=f(5-1)+1.75=f(4)+1.75=0+1.75→f(5)=1.75
Answer:
Sequence of the terms:
First, second, third, fourth, fifth:
-5.25, -3.5, -1.75, 0, 1.75
(2) = -1/5(4) + 3
y= -1/5x - 1/5
Answer:
D
Step-by-step explanation:
R-9s=2 add 9s to both sides
r=2+9s making 3r-3s=-10 become:
3(2+9s)-3s=-10 perform indicated multiplication on left side
6+27s-3s=-10 combine like terms on left side
6+24s=-10 subtract 6 from both sides
24s=-16 divide both sides by 24
s=-16/24
s=-2/3, making r-9s=2 become:
r-9(-2/3)=2 perform indicated multiplication on left side
r+6=2 subtract 6 from both sides
r=-4
So s= -2/3 and r= -4
