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tigry1 [53]
3 years ago
10

Tickets to a play cost $14 each by mail, plus a $2 processing fee for each order or one or more tickets. Write a rule to describ

e the total cost as a function of the number of tickets.
Mathematics
1 answer:
Aneli [31]3 years ago
6 0
The equation would be 14x+2=t......

Breakdown: 14 times X (the number of tickets purchased) plus the one time processing fee of 2 dollars will equal T (the total)
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I will mark you brainiest if you can answer this
nata0808 [166]
1. C (2,2)
2. H (-9,-5)
3. B (-2,6)
4. E (8,-4)
5. G (-4,-2)
6. ( 6,8)
7. A (-8,4)
8. F (4,-9)
6 0
2 years ago
What is one of the solutions to the following system of equations? y2 x2 = 53 y − x = 5 (−10, −5) (−7, −2) (7, 2) (5, 10).
Aliun [14]

The solution of the system of equation is (-7, -2).

<h2>Given</h2>

The system of the equations;

\rm y^2 + x^2 = 53 \\\\y -x = 5

From equation 1

\rm  y -x=5\\\\y = 5+x

Substitute the value of y in equation 1

\rm y^2+x^2=53\\\\(5+x)^2+x^2=53\\\\25+x^2+10x+x^2=53\\\\2x^2+10x+25-53=0\\\\2 x^2 + 10x - 28 = 0     \\\\Divide \ by \ 2 \ both \ side \ the \ equation\\\\x^2 + 5x - 14 = 0\\\\x^2-7x+2x-14=0\\\\x(x-7) + 2(x-7) =0\\\\(x-7) \ (x+2)=0\\\\x-7=0 \ \ x = 7\\\\x +2 =0 \ \ x=-2

The value of x= 2 is rejected because x = 2 not satisfy the equation.

Substitute 2 for the value of x in equation II

y − x = 5

y – 2 = 5

y = 5 +2

y = 7 (x =2, y =7) … Not included in the options

If x = -7

Substitute the value of x = -7 in the equation

\rm y -x=5\\\\y - (-7)=5\\\\y +7= 5\\\\y = 5-7\\\\y = -2

Hence, the solution of the system of equation is (-7, -2).

To know more about System of Equation click the link given below.

brainly.com/question/1495351

6 0
2 years ago
Find an expression for the nth term ( tn ) in each of the following sequences:
Alexandra [31]

Answer:

The expression for the nth term is Tn = 8n -7

Step-by-step explanation:

Here, we are to find an expression for the nth term of the sequence.

Mathematically, the nth term of an arithmetic sequence can be expressed as;

Tn = a + (n-1)d

for T2, the equation is

a + d = 9

for T4, the equation is

a + 3d = 25

we can substitute the equation of T2 into T4 but we first need to rewrite T4

a + d + 2d = 25

9 + 2d = 25

2d = 25 -9

2d = 16

d = 16/2

d = 8

now since a + d = 9

a = 9-d

a = 9-8

a = 1

So the expression for the nth term would be;

1 + (n-1)8

1 + 8n - 8

= 8n -8+1

= 8n -7

6 0
3 years ago
A basketball court is in the shape of a rectangle. It has a length of (x - 7) meters and a width of (x + 3) meters:
Molodets [167]

Answer:

x2 - 4x - 21

Step-by-step explanation:

Area = (x -7 )(x +3)

= x*x - 7*x + x*3 - 7*3

=x2 - 4x - 21

5 0
3 years ago
Find all solutions of the equation in the interval [0, 2π). cotθ+ √3= 0
Ilia_Sergeevich [38]

Answer:

  {5π/6, 11π/6}

Step-by-step explanation:

Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.

The solution to this equation is ...

  cot(θ) = -√3

so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.

5 0
2 years ago
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