1. C (2,2)
2. H (-9,-5)
3. B (-2,6)
4. E (8,-4)
5. G (-4,-2)
6. ( 6,8)
7. A (-8,4)
8. F (4,-9)
The solution of the system of equation is (-7, -2).
<h2>Given</h2>
The system of the equations;

From equation 1

Substitute the value of y in equation 1

The value of x= 2 is rejected because x = 2 not satisfy the equation.
Substitute 2 for the value of x in equation II
y − x = 5
y – 2 = 5
y = 5 +2
y = 7 (x =2, y =7) … Not included in the options
If x = -7
Substitute the value of x = -7 in the equation

Hence, the solution of the system of equation is (-7, -2).
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Answer:
The expression for the nth term is Tn = 8n -7
Step-by-step explanation:
Here, we are to find an expression for the nth term of the sequence.
Mathematically, the nth term of an arithmetic sequence can be expressed as;
Tn = a + (n-1)d
for T2, the equation is
a + d = 9
for T4, the equation is
a + 3d = 25
we can substitute the equation of T2 into T4 but we first need to rewrite T4
a + d + 2d = 25
9 + 2d = 25
2d = 25 -9
2d = 16
d = 16/2
d = 8
now since a + d = 9
a = 9-d
a = 9-8
a = 1
So the expression for the nth term would be;
1 + (n-1)8
1 + 8n - 8
= 8n -8+1
= 8n -7
Answer:
x2 - 4x - 21
Step-by-step explanation:
Area = (x -7 )(x +3)
= x*x - 7*x + x*3 - 7*3
=x2 - 4x - 21
Answer:
{5π/6, 11π/6}
Step-by-step explanation:
Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.
The solution to this equation is ...
cot(θ) = -√3
so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.