Question

Using the order of operations , solve the value of the expression.

Answer 1

Hello.

$\frac{1}{6} (\sqrt{36} \div 3^{-2}) + 4^{3} \div |-8| = \\ \\ \frac{1}{6} (6 \div \frac{1}{9}) + 64 \div 8 \\ \\ \frac{1}{6} \times 54 + 8 \\ \\ \frac{54}{6} + 8 \\ \\ 9 + 8 = \\ \\ 17$

Hope I helped!