So first you find 10% which is 34.5
Then you multiply 10% by 4 to get 40% which is = 138
Hello there!
This is a conceptual question about quadratic functions.
Remember that a solution of ANY function is where it intersects the x-axis, so if the quadratic function intersects the x-axis TWO times, this means that there are TWO real solutions.
Here's a list of things to remember that will help you out for quadratic functions...
•if a quadratic function intersects the x-axis twice, it has two real solutions.
•if a quadratic function intersects the x-axis once, it has one real solution and one imaginary solution.
•if a quadratic function intersects the x-axis zero times, it has zero deal solutions and two imaginary solutions.
Please NOTE: If you want to know how many solutions a polynomial function has, look at it's highest exponent. If it is 2, then it has 2 solutions whether they be real or imaginary. If it is 3, then it has 3 solutions.
Also, if one of the factors are the same for a polynomial function, the way it hits the x-axis changes! This is just some extra information to help you in the long run!
I hope this helps!
Best wishes :)
Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1
