Answer:
0.8973
Step-by-step explanation:
Relevant data provided in the question as per the question below:
Free throw shooting percentage = 0.906
Free throws = 6
At least = 5
Based on the above information, the probability is
Let us assume the X signifies the number of free throws
So, Then X ≈ Bin (n = 6, p = 0.906)
Now
The Required probability = P(X ≥ 5) = P(X = 5) + P(X = 6)
= 0.8973
Answer:
Wednesday (9 weeks later) = 10th October.
Step-by-step explanation:
We label the days with the initials of the names.
M= 4
D = 7
B = 6
LCM of 6 +7 = 42
LCM of 6+7 + 4 = 84
We find 84 is the amount of days we need to add on to july 18th
We first find the weeks 84/7 = 9 weeks.
As Wednesday July 18th is exclusive it would be 84 days after this event.
18+ 84 = 102 days.
31 days in july = 31
31 days in Aug = 31
30 days in Sept = 30
= 92
102-92 = 10
We now know date is Wednesday 10th October
We can check 84 days = 9 weeks
13 days in July makes 31st july
31 days in Aug makes 31st Aug
30 days in Sept makes 30th Sept
= 74 days + 10 days = 84
10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.
Answer:
maybe rotation.........i think....
If the base is 2 and the exponent is the the expression would look like this → 2³. In order to simplify it, you have to multiply the base number by the number of the exponent.
2×2×2=8
Therefore, the simplified expression would be 8.
I hope this helped.
Yes
remember you can do anything to an equaiton as long as you do it to boh sides
ad try to get unknown to one side
9n-10=4n+10
minus 4n both sides
9n-4n-10=4n-4n+10
5n-10=0+10
add 10
5n+10-10=0+10+10
5n+0=20
5n=20
divide both sies by 5
5n/5=20/5
5/5n=4
1n=4
n=4
