Please Help and Thanks.

Mathematics

1 answer:

Katena32 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

case 1

cost of 20oz bottle of soda = $1.20

dividing both side by 20

cost of 20/20 oz bottle of soda = $1.20/20

cost of 1oz bottle of soda = $0.06

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Case 2

cost of 12oz bottle of soda = $0.85

dividing both side by 12

cost of 20/20 oz bottle of soda = $0.85/12

cost of 1oz bottle of soda = $0.07

Based on above calculation, we can see that first deal 20oz bottle of soda at costs $1.20 is better deal as per unit cost is $0.06 which is less than 12 oz can of soda costs $0.85 which is equivalent to $0.07 per unit cost

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What is the answer a or b to this question

galina1969 [7]

The answer would be A.

Explanation:

If they enter with one car, that’s a price of $3 for the car alone. Because there’s also a fee for each person who enters, and there is a family of 5 who enters, x is representative of the cost for each person who enters. Therefore, there would be 5 x’s and one 3 that when solved would add up to the total of $45 they spent. That would mean A is correct because the equation would be x + x + x + x + x + 3 = 45.

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1 year ago

A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1200 hours and a standar

a_sh-v [17]

Answer:

The bulbs should be replaced each 1060.5 days.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1200, \sigma = 60$