We have to use the functions: h ( x ) = 2 x + 5 and t ( x ) = 7 x - 6 Part A: ( h + t ) ( x ) = ( 2 x + 5 ) + ( 7 x - 6 ) = 9 x - 1 Part B : ( h · t ) ( x ) = ( 2 x + 5 ) · ( 7 x - 6 ) = 14 x² - 12 x + 35 x - 30 = = 14 x² + 23 x - 30 Part C : h [ t ( x ) ] = h ( 7 x - 6 ) = 2 · ( 7 x - 6 ) + 5 = 14 x - 12 + 5 = = 14 x - 7
The formula for finding the surface area of a cube is A=6y^2 where y is the side length. we know a=96. so we just isolate y. 96/6= 6y^2 / 6 16=y^2 sqrt (16) = sqrt(y^2) 4=y
