Question

There are 4 red and 6 green marbles in a jar. What is the probability of drawing two green marbles, with replacement?

Answer 1

Answer:

$\frac{9}{25}$

Step-by-step explanation:

Number of red balls = 4

Number of green balls = 6

Total number of balls = 6+4 =10

Probability of drawing a green marble is given as

⇒ $\frac{Number\ of\ green\ balls}{Total\ number\ of\ balls}$

⇒ $\frac{6}{10}$

The ball is replaced after drawing.

Probability of drawing a green ball a second time will be:

⇒ $\frac{Number\ of\ green\ balls}{Total\ number\ of\ balls}$

⇒ $\frac{6}{10}$

Thus, probability of drawing 2 green balls with replacement can be given as:

⇒  (Probability of drawing a green marble) $\times$ (Probability of drawing a green ball a second time)

⇒ $\frac{6}{10}\times\frac{6}{10}$

⇒ $\frac{36}{100}$

Simplifying fraction by dividing numerator and denominator by their GCF.

⇒ $\frac{36\div 4}{100\div 4}$

⇒ $\frac{9}{25}$ (Answer)