Question

Which shows all the exact solutions of sin^2 x + 3cos x - 1 = 2?

Answer 1

Answer:

x = 2k$\pi$ is the solution of this equation.

Step-by-step explanation:

This question is related to trigonometric equations.

The given equation is,

$sin^{2} x + 3cos x - 1 = 2$

We have to find the solutions of this equation.

Put $sin^{2}x = 1 - cos^{2}x$

$1 - cos^{2}x$ + 3cosx - 1 = 2

$cos^{2}x -3cosx+2$ = 0

For this equation only cosx = 1 is possible solution.

Cosx = 1 happens when x is a multiple of 2$\pi$

So x = 2k$\pi$ is the solution of this equation.