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If a person bikes 2.4 miles in 10 minutes how far can he bike in 30 min

Sedaia [141]

Answer:

They can bike 7.2 miles in 30 minutes.

Step-by-step explanation:

2.4 * 3 = 7.2

7 0

3 years ago

Plssss helpp brainliest will b givenn

omeli [17]

Answer:

15

Step-by-step explanation:

7 0

3 years ago

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4. If your company purchases an annuity that will pay $50,000/year for 10 years at a 11% discount rate, what is the value of the

julsineya [31]

Answer:

The value of the annuity is $326,852.3766.

Step-by-step explanation:

Here is the required formula to find the present value of annuity:

We can find the present value of annuity:

$PV = P + P (\frac{1-(1+r)^{-(n-1)} }{r})$

Here:

P = $50,000

n = represents the number of number of periods

r = 0.11

$PV = 50,000 + 50,5000 (\frac{1-(1+0.11)^{-(10-1)} }{0.11})$

PV = $326,852.3766

The value of the annuity is $326,852.3766 i.e. PV = $326,852.3766.

Keywords: discount rate, present value of annuity

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4 0

3 years ago

Evaluate the expression below<br> a - cd for a = -2, c = 5, d = -3|

Svetllana [295]

-2-(5•-3)= -2-(-15)
= -2+15
=13

4 0

3 years ago

The marketing manager for an automobile manufacturer is interested in determining the proportion of new compact-car owners who w

Serhud [2]

Answer:

$z=\frac{0.395 -0.3}{\sqrt{\frac{0.3(1-0.3)}{200}}}=2.932$

$p_v =2*P(z>2.932)=0.0034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of people that they would have purchased the GPS navigation system is significantly different from 0.3

Step-by-step explanation:

Data given and notation

n=200 represent the random sample taken

X=79 represent the number of people that they would have purchased the GPS navigation system

$\hat p=\frac{79}{200}=0.395$ estimated proportion of people that they would have purchased the GPS navigation system

$p_o=0.3$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.3 or no.:

Null hypothesis: $p=0.3$

Alternative hypothesis: $p \neq 0.3$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.395 -0.3}{\sqrt{\frac{0.3(1-0.3)}{200}}}=2.932$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.932)=0.0034$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of people that they would have purchased the GPS navigation system is significantly different from 0.3

4 0

3 years ago