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chubhunter [2.5K]
3 years ago
14

NEED HELP FAST PLEASE PROVIDE WORK SO I KNOW YOU KNOW WHAT YOUR DOING

Mathematics
1 answer:
pashok25 [27]3 years ago
5 0
Okay well, if you make a graph, Point A (7,0) and Point B (4,6) are in the top right quadrant. and Point C (1,1) and Point D (5,3) are in the top left, top right, and bottom left quadrant (I'll link a photo of the graph.)
so the lines intersect and make it perpendicular



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Trapezia ABCD and PQRS are similar.<br> Find the area shaded in green.
avanturin [10]

The area shaded in green is 864 cm²

<h3>Similar figures</h3>

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let find the height of trapezium PQRS.

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Therefore,

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<h3>Area of a trapezium</h3>
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Therefore,

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area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²

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learn more on trapezium here: brainly.com/question/11961445

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