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chubhunter [2.5K]
3 years ago
14

NEED HELP FAST PLEASE PROVIDE WORK SO I KNOW YOU KNOW WHAT YOUR DOING

Mathematics
1 answer:
pashok25 [27]3 years ago
5 0
Okay well, if you make a graph, Point A (7,0) and Point B (4,6) are in the top right quadrant. and Point C (1,1) and Point D (5,3) are in the top left, top right, and bottom left quadrant (I'll link a photo of the graph.)
so the lines intersect and make it perpendicular



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Help please will vote you as brainliest
ddd [48]
Number 1 is A
number 2 is C
number 3 is A
8 0
4 years ago
Which of the following is not an example of like terms?
Viktor [21]

Answer:

A. 2 and-6

Step-by-step explanation:

Like terms are terms that contain the same variables raised to the same powers. In other words, they have the same variables with the same exponents.

So in option A, we have the terms 2 and -6. These terms are not like terms because they do not have the same variables.

4 0
2 years ago
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in gym class, you run 3/5 mile. your coach runs 10 times that distance each day. how far does your coach run each day?
Feliz [49]
The coach runs 6 miles each day. Because you would do 3 divided by 5, and get 0.6. Then times that by 10 and you get 6.
3 0
3 years ago
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HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
The point halfway between two end points of a line segment is a
Liula [17]
The point halfway between two end points is called a midpoint
3 0
3 years ago
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