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SashulF [63]
4 years ago
5

Help with math alg 2

Mathematics
1 answer:
Luda [366]4 years ago
7 0
Im so sorry i have no idea and i dont want to you to ge the question wrong because of me im sorry
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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
use the formula to calculate how much the district spent on athletics in 1999. round your answer to the nearest thousandth
Vesnalui [34]
<span>10.6325909767 rounded to the nearest 10th is 10.633</span>
4 0
3 years ago
A part of a line with endpoints on both ends is a(n):
patriot [66]

I believe it's a segment.

4 0
4 years ago
3≤7+g<br><br> Help <br><br><br> I’m famous
oee [108]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Let's solve your inequality step-by-step.

3 ≤ 7 + g

Step 1:Simplify both sides of the inequality.

3 ≤ g + 7

Step 2: Flip the equation.

g + 7 ≥ 3

Step 3: Subtract 7 from both sides.

g + 7 − 7 ≥ 3 − 7

g ≥ −4

Answer:

g ≥ −4

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

8 0
3 years ago
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Im not understanding this question
natita [175]

It's said "The value √-9 is not -3 because --------------------

So you need to prove why -3 is not the value of √-9.


As you know (-3)^2 = (-3) * (-3) = 9, ≠ -9


Answer is A. 

(-3)^2 ≠ -9

7 0
3 years ago
Read 2 more answers
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