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True [87]
4 years ago
5

What is 6.89 divided by 2 ????????

Mathematics
2 answers:
Ierofanga [76]4 years ago
8 0
The answer is 3.445.
Firdavs [7]4 years ago
6 0
The correct answer is 3.445 , but if you round it you get 3.45
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How do you find the other angle of an alternate interior angle if one angle is 70
Elena L [17]
Well alternate angles are congruent, so that means they would both have the same measurement.
If you’re talking about equations with an angle then make the equations equal each other and solve. :)
4 0
3 years ago
What is the slope of the line on the graph?<br><br><br><br> Enter your answer in the box.
alexira [117]
To find the slope,we can use the slope formula:
\frac{y1 - y2}{x1 - x2}
Where x and y are y coordinates and x coordinates respectively.

To find the answer, put any two points into the formula.

In this case, (1,5) and (0,-1) will be used:

x1 and y1 would be the x and y coordinate in the first point(1,5), while x2 and y2 would be the x and y coordinate in the first point (0,-1)

\frac{5 - ( - 1)}{ 1- 0}  \\  =  \frac{5 + 1}{1}  \\   = \frac{ 6}{1}  \\  = 6
Therefore the answer is 6.

Hope it helps!
5 0
4 years ago
Determine the ordered pair that satisfies the equation, -5x - 6y = -8. A (8 ,−163−163) B (-5 , -6) C (8 , 8) D (5 ,−225−225) E I
hjlf
I'm guessing D, but not too sure.
7 0
3 years ago
Assume you are given a boolean variable named isRectangular and a 2-dimensional array that has has been created and assigned to
Savatey [412]

Answer:

nElements = 0;

for (int i = 0; i < a2d.length; i++)

nElements += a2d[i].length;

isRectangular = true;

for (int i = 1; i < a2d.length && isRectangular; i++)

if (a2d[i].length != a2d[0].length)

isRectangular = false;

Step-by-step explanation:

2 dimensional array is created and  initialize element with 0. and the taking loop for 2 dimensional array .such as

n Elements = 0;

for (int i = 0; i < a2d.length; i++)

n Elements += a2d[i].length;

A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.

If rectangular is false then  apply if statement  and see if a2d[i] is not equal to a2d[0]

if (a2d[i].length != a2d[0].length)

isRectangular = false;

4 0
4 years ago
Monica says since all squares are rectangles, all rectangles are squares is she correct explain
AysviL [449]

Answer:

no, rectangles have 2 sets of parallel sides but in a square all sides are parallel

5 0
3 years ago
Read 2 more answers
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