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Greeley [361]
4 years ago
14

Plz i gotta turn it in today

Mathematics
1 answer:
mel-nik [20]4 years ago
4 0

2) B

3) C

it my answer it mybe not true

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Solve the equation 4x^2 – 32x + 64 = 0.
AlexFokin [52]

Answer: x = 4

Step-by-step explanation:  4x^2−32x+64=0

4(x−4)(x−4)=0

x−4=0 x−4=0

x=4

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2 years ago
Can somebody help with geometry?
GaryK [48]

Step-by-step explanation:

You can look this answers up off the paper and find the worksheet

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3 years ago
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Lapatulllka [165]
It’s is 6 because I added it all up and all you have to do is division
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3 years ago
The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]

By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
How to rewite this x+4y=-4 in form y=mx+b
Alex
x+4y=-4\\&#10;4y=-x-4\\&#10;y=-\frac{1}{4}x-1
3 0
3 years ago
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