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Lynna [10]
3 years ago
14

. double x = 5; declares that x is a...............variable.

Computers and Technology
1 answer:
brilliants [131]3 years ago
7 0

Answer:

x is a double type variable.

Explanation:

Here is x is a variable of type double which stores the value 5. The main purpose of a double datatype is storing the decimal point values. The precision of double datatype is two times more than the precision of float datatype. So on displaying the value of x in c++ it prints "5".

Following are the program of double datatype in c++

#include <iostream> // header file

using namespace std; // namespace  

int main() // main function

{

  double x=5; // variable declaration

  cout<<x; // displaying the value of x

  return 0;

}

Output:

5

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Write a program that prompts the user to enter their name store this value in a variable called name Prompt the user for their c
Anarel [89]

Answer:

Explanation:

The following code is written in Python. It prompts the user for the name and age, saves them to their own variables. Then it creates and calculates the dogAge variable. Finally, it combines all of this information and prints out the statement.

name = input("Enter your name: ")

age = input("Enter your age: ")

dogAge = int(age) * 7

print("Your name is", name, "and in dog years you are", dogAge, "years old.")

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2 years ago
What is the name of a button on a website?
zhuklara [117]
May I know which button?
5 0
3 years ago
Extend to also calculate and output the number of 1 gallon cans needed to paint the wal. Hint: Use a math function to round up t
Crank

Answer:

Here is the Python program:

import math #import math to use mathematical functions

height = float(input("Enter wall height (feet): ")) #prompts user to enter wall height and store it in float type variable height

width = float(input("Enter wall width (feet): ")) #prompts user to enter wall width and store it in float type variable width

area = height *width #computes wall area

print('Wall area: {} square feet'.format(round(area))) #displays wall area using round method that returns a floating-point number rounded

sqftPerGallon = 350 #sets sqftPerGallon to 350

paintNeeded = area/ sqftPerGallon #computes needed paint

print("Paint needed: {:.2f} gallons".format(paintNeeded)) #displays computed paint needed up to 2 decimal places

cansNeeded = int(math.ceil(paintNeeded)) #computes needed cans rounding the paintNeeded up to nearest integer using math.ceil

print("Cans needed: {} can(s)".format(cansNeeded)) #displays computed cans needed

colorCostDict = {'red': 35, 'blue': 25, 'green': 23} #creates a dictionary of colors with colors as key and cost as values

color = input("Choose a color to paint the wall: ") #prompts user to enter a color

if color in colorCostDict: #if the chosen color is present in the dictionary

    colorCost = colorCostDict.get(color) #then get the color cost from dictionary and stores it into colorCost using get method that returns the value(cost) of the item with the specified key(color)

    cost = cansNeeded * colorCost #computes the cost of purchasing paint of specified color per cansNeeded

  print("Cost of purchasing {} paint: ${}".format(color,colorCostDict[color])) #displays the real cost of the chosen color paint

print("Cost of purchasing {} paint per {} gallon can(s): ${}".format(color,cansNeeded, cost)) #displays the cost of chosen color paint per cans needed.

Explanation:

The program first prompts the user to enter height and width. Lets say user enter 20 as height and 50 as width so the program becomes:

Wall area computed as:

area = height *width

area = 20 * 50

area = 1000

Hence the output of this part is:

Wall area: 1000 square feet                                                                                                                     Next program computes paint needed as:

paintNeeded = area/ sqftPerGallon

Since sqftPerGallon = 350 and area= 1000

paintNeeded = 1000 / 350

paintNeeded = 2.86

Hence the output of this part is:

Paint needed: 2.86 gallons

Next program computes cans needed as:      

cansNeeded = int(math.ceil(paintNeeded))

This rounds the computed value of paintNeeded i.e. 2.86 up to nearest integer using math.ceil so,

cansNeeded = 3                                                                  

Hence the output of this part is:

Cans needed: 3 can(s)                                                                                                                            Next program prompts user to choose a color to paint the wall

Lets say user chooses 'blue'

So the program get the cost corresponding to blue color and multiplies this cost to cans needed to compute the cost of purchasing blue paint per gallon cans. So

cost = cansNeeded * colorCost

cost = 3 * 25

cost = 75

So the output of this part is:

Cost of purchasing blue paint per 3 gallon can(s): $75                                                                                        The screenshot of the program along with its output is attached.

5 0
3 years ago
A file with a com extension is most likely to be a(n) ___ file.
olasank [31]
I think that the answer is: A executable
4 0
3 years ago
Read 2 more answers
How many bits does it take to store a 3-minute song using an audio encoding method that samples at the rate of 40,000 bits/secon
blondinia [14]

Answer:

115200000 bits

Explanation:

Given Data:

Total Time = 3 minute = 3 x 60 sec = 180 sec

Sampling rate = 40,000 bits / sample

Each sample contain bits = 16 bits /sample

Total bits of song = ?

Solution

Total bits of song = Total Time x Sampling rate x Each sample contain bits

                             = 180 sec x 40,000 bits / sec x 16 bits /sample

                             = 115200000 bits

                             =  115200000/8 bits

                             = 14400000 bytes

                             = 144 MB

There are total samples in one second are 40000. Total time of the song is 180 seconds and one sample contains 16 bits. so the total bits in the song are 144 MB.

5 0
3 years ago
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