Answer:
It's asking for a reflection. The point D is 5 points lower than the line, so the plot dot should be 5 points higher than the line, right above the other D point. Think of the line as a mirror.
The red dot in the attached image is the answer.
Answer:
9x² - 6x
Step-by-step explanation:
Thats the answer in edgenuity student :)
Answer: a. 30x^2 − 26x − 12
First write the equation in a form to better help visualize.
(5x - 6)(6x + 2)
Then use distributive property on the second binomial from the first binomial. <em>You multiply 5x by 6x and 2, then multiply -6 by 6x and 2.</em>
5x * 6x = 30x^2 (The answer is raised to the power of 2 because you're adding the invisible exponents, aka exponents of 1)
Then multiply 5x by 2
5x * 2 = 10x
Then you repeat the process but with -6 instead of 5x.
-6 * 6x = -36x (It is not raised to a power of 2 because -6 does not have a variable to include the invisible exponent)
-6 * 2 = -12
Now take all of your answers and put them into 1 equation by the order you did them.
30x^2 + 10x - 36x -12
But wait! The answer can still be simplified. All you have to do is combine like terms. <em>However 30x^2 can't be combined with 10x because 10x isn't raised to the second power, terms can only be combined if they have the same variable and exponent.</em>
30x^2 + (10x - 36x) - 12
30x^2 - 26x - 12
First, let's write the given equation in slope-intercept form: y = mx + b
In slope-intercept form, the slope of the line is m, and the y-intercept is b. The slope is a measure of how steep the graph is at any point and is found by doing rise over run. This means the change in y values divided by the change in x values. Next, y-intercept is just where the graph crosses the y axis.
All we need to do to get the equation in slope-intercept form is to divide each term by 3. This will isolate the y.
As you can see, the slope of the line is 2/3, and the y-intercept is -2.
To graph the line, plot a point at (0,-2). This is the point where the graph crosses the y axis. Then from that point, count up two and right 3. Plot a point here as well. Lastly, connect the two points with a straight line.
See attached picture for the graph.
