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Kipish [7]
3 years ago
6

A sphere with radius r and a cylinder with radius r and a height of r are shown below. How do the surface areas of these solid f

igures compare? Which statements are correct? Check all that apply. The surface area of the sphere in terms of r is 4πr2 square units. The surface area of the cylinder in terms of r is 4πr2 square units. The surface area of the cylinder in terms of r is 6πr2 square units. The surface area of the cylinder and sphere are the same. The surface area of the cylinder and sphere are not the same.
Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0

Answer:

  • The surface area of the sphere in terms of r is 4πr^2 square units.
  • The surface area of the cylinder in terms of r is 4πr^2 square units.
  • The surface area of the cylinder and sphere are the same.

Step-by-step explanation:

The surface area of the sphere is given by the formula ...

  A = 4πr^2

The surface area of the cylinder is given by the formula ...

  A = 2πr^2 +2πrh

Here, the height (h) is equal to r, so this simplifies to ...

  A = 2πr^2 +2πr·r = 4πr^2 . . . . . the same area as the sphere

kykrilka [37]3 years ago
7 0

Answer:

A, B, and D are the correct answers (Edge)

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Answer:

What you are looking at is a scalene triangle!

Step-by-step explanation:

By definition scalene triangles are triangles where each side is a different length... hope this one helps you!

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A triangle has vertices at (4,3), (-2,4), and (-4, 2). What are the coordinates of the vertices of the image
Alexeev081 [22]

The coordinates are (4,3) ►(6,-2)

(-4,2) ►(-2,-3)

. (-2,4) →(0,-1)

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What is the average rate of change of the function over the interval x = 0 to x = 6? f(x)=2x−1 3x+5 Enter your answer, as a frac
Tatiana [17]

Answer:

-11

Step-by-step explanation:

Our function is 2x-13x+5

  • 2x-13x+5= -11x+5
  • F(0)= 5 and F(6)= -11*6+5 = -61
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8 0
3 years ago
Which number would make the statement true? (2 points)
alexandr402 [8]

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0.253

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since it is greater than 0.243

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Need help with homework
motikmotik

We have two points describing the diameter of a circumference, these are:

\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}

Recall that the equation for the standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Now, we replace and solve:

\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}

The center of the circle is (-8,-7), so:

\begin{gathered} h=-8 \\ k=-7 \end{gathered}

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

r^2=\Delta x^2+\Delta y^2

In this case, we will solve the delta with the center coordinate and the B coordinate.

\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}

Therefore, the equation for the standard form of a circle is:

\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}

In conclusion, the equation is the following:

(x+8)^2+(y+7)^2=25

4 0
1 year ago
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