Ask question

Ask question

All categories

2 years ago

13

Dan is making bags of trail mix for hiking club. He will use 23 ounces of walnuts, 10.2 ounces of almonds, and 13.3 ounces of ca

shews. This amount makes 25 bags of trail mix. How many ounces are in each bag?

1 answer:

aleksley [76]2 years ago

3 0

Answer:

There will be 1.86 ounces per bag

Step-by-step explanation:

We can analyze the problem in this manner: We can assume that DAN mixes all his ingredients into a big pile before he shares them into the 25 bags. This way we can find the weight of what is in each of the bags, assuming he shares the trail mix equally among the 25 bags.

When he mixes the ingredients into a big pile, the total weight of the pile will be equals to the weight of all the ingredients summed up.

This will be 23 ounces + 10.2 ounces + 13.3 ounces = 46.5 ounces

He will now be sharing the 46.5 ounces into the 25 available bags.

This will give 46.5 ÷25 = 1.86 ounces per bag.

There will be 1.86 ounces per bag

You might be interested in

8. Tell whether the system has one solution, infinitely many solutions, or no solution. 6y=-5x+24

Sophie [7]

The correct answer is B

7 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

Exponent Practice:<br> x^2/3=64

docker41 [41]

X^2/3 = 64
$x^{2} =64^{3}$
$x = 64^{3/2}$

it is easier to first find square root of 64 and than power it to 3
square root of 64 is 8 which means our equation now looks like:
x = 8^3
now the answer is after powering 8 to 3:
x = 512

6 0

3 years ago

Choose the correct word that completes each statement about inscribing a square in a circle.

Anna11 [10]

Answer:

1. Perpendicular

2. Isosceles

3. Never

Step-by-step explanation:

1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.

2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )

In Δ COB , By using pythagoras : BC² = OC² + OB² ..........( 2 )

But, OA = OC because both are radius of same circle

So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC

⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.

3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius

7 0

2 years ago

Find X and y<br><br> 12, 16

zavuch27 [327]

Answer:

x = 6√2
y = 6√6

Step-by-step explanation:

The triangles are all similar, so corresponding sides are proportional.

__

<h3>x</h3>

long side/short side = x/6 = 12/x

x² = 72 . . . . . . . multiply by 6x

x = 6√2 . . . . . . take the square root

__

<h3>y</h3>

hypotenuse/long side = y/12 = (12+6)/y

y² = 216 . . . . . multiply by 12y

y = 6√6 . . . . . take the square root

8 0

2 years ago