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Helga [31]
3 years ago
9

2 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0

Answer:

This series is divergent

F

Step-by-step explanation:

we are given a series

Firstly, we will find nth term

Numerator:

3, 4, 5,...

so, nth term will be

a_n=n+3

Denominator:

4,5,6,....

so, nth term will be

b_n=n+4

so, we can find it's nth term as

c_n=\frac{n+3}{n+4}

we can use divergent test

\lim_{n \to \infty}  c_n=\lim_{n \to \infty} \frac{n+3}{n+4}

we can divide top and bottom by n

\lim_{n \to \infty}  c_n= \lim_{n \to \infty} \frac{n/n+3/n}{n/n+4/n}

\lim_{n \to \infty}  c_n= \lim_{n \to \infty} \frac{1+3/n}{1+4/n}

now, we can plug n=inf

\lim_{n \to \infty}  c_n= \frac{1+0}{1+0}

\lim_{n \to \infty}  c_n=1

Since, it is non-zero value

so, this series is divergent


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