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Alex73 [517]
2 years ago
14

Round the number to the hundredths place. 26,379.87492 A. 26,379.87 B. 26,379.88 C. 26,380 D. 26,400

Mathematics
1 answer:
LuckyWell [14K]2 years ago
7 0
Your answer would be D 26400


I hope it's right
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Select the correct answer.
shutvik [7]
B is the answer but check if u can simplify it
3 0
3 years ago
HELP ME PLEASE !!!!!!!!!!15 POINTS 
USPshnik [31]

C is the correct answer 3.785*2.5=9.4625 then multiply by 1000 and you get 9,462.5

3 0
3 years ago
Read 2 more answers
Books spontaneously catch on fire in temperatures at or above 451, degree Fahrenheit. Write an inequality that is true only for
Brilliant_brown [7]
For this case, the first thing you should do is define a variable.
 We have then:
 t: temperature (degree Fahrenheit).
 We write then the inequation that adapts to the problem:
 t> = 451
 Answer:
 
an inequality that is true only for temperatures at which books spontaneously catch on fire is:
 
t> = 451
3 0
3 years ago
The centers for disease control and prevention reported that 25% of baby boys 6-8 months old in the united states weigh more tha
melisa1 [442]

Answer:

0.1971 ( approx )

Step-by-step explanation:

Let X represents the event of weighing more than 20 pounds,

Since, the binomial distribution formula is,

P(x)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

Given,

The probability of weighing more than 20 pounds, p = 25% = 0.25,

⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75

Total number of samples, n = 16,

Hence, the probability that fewer than 3 weigh more than 20 pounds,

P(X

=^{16}C_0 (0.25)^0 (0.75)^{16-0}+^{16}C_1 (0.25)^1 (0.75)^{16-1}+^{16}C_2 (0.25)^2 (0.75)^{16-2}

=(0.75)^{16}+16(0.25)(0.75)^{15}+120(0.25)^2(0.75)^{14}

=0.1971110499

\approx 0.1971

3 0
3 years ago
I need help with this question i dont understand it
RUDIKE [14]
The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2}  }
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
\sqrt{(3-2) ^{2}+(4-3) ^{2}  }
which simplifies to
\sqrt{(1 )^{2}+(1) ^{2}  } which is \sqrt{2}
So that is the length of both MN and LM.  So far our perimeter is \sqrt{2} + \sqrt{2}=2 \sqrt{2}
Now let's use the same formula to find out the length of one of the longer segments:
\sqrt{(5-3) ^{2} +(3-2) ^{2} }
which simplifies down to
\sqrt{(2) ^{2} +(1) ^{2} }
which is of course \sqrt{5}
Since we have 2 of those lengths, \sqrt{5} + \sqrt{5}=2 \sqrt{5}
So our perimeter is, in the end, 2 \sqrt{2}+2 \sqrt{5}
That's the third choice down
7 0
2 years ago
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