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Solnce55 [7]
3 years ago
13

Help with these, if theyre right, ill give brainliest

Mathematics
2 answers:
adelina 88 [10]3 years ago
3 0

Answer:

q1: yes

q2: no

Step-by-step explanation:

2(5)+10(1)=20

10+10=20

20=20

(5)+(1)=6

5+1=6

6=6

(8)=(1)+3

8=1+3

8=4

gregori [183]3 years ago
3 0
Answer is q1. yes q2. no
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-x - 4y = 16 find value of y when x equals -8
pashok25 [27]
The answer is -2......
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3 years ago
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on an avrage saturday, 15% of tickets sold are child tickes. if there were 460 tickets sold on saturday then how many were sold
Ede4ka [16]

Answer:

69 child tickets

Step-by-step explanation:

0.15 x 460 = 69

8 0
3 years ago
A dietitian wants to know the average time spent on breakfast in a primary school. The dietitian randomly samples 25 students an
blsea [12.9K]

Answer:

The right options are:

a. The margin of error is 0.632

f. There is a 95% chance that the true mean is between 11.968 and 13.232 minutes.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>Select one or more:</em>

<em>a. The margin of error is 0.632</em>

<em>b. The margin of error is 1264.</em>

<em>C. The margin of error is 0.600.</em>

<em>d. We believe that the true mean time spent on breakfast is between 11.968 and 13.232 minutes.</em>

<em>e. If we take many other samples from this population, 95% of them will have a sample mean that is between 11968 and 13232.</em>

<em>f. There is a 95% chance that the true mean is between 11.968 and 13.232 minutes.</em>

The margin of error can be calculated from the bounds of the confidence interval as:

E=\dfrac{UL-LL}{2}=\dfrac{13.232-11.968}{2}=\dfrac{1.264}{2}=0.632

As the confidence interval is calculated at 95% confidence, we are 95% confident that the true mean is within the calculated interval. We are not 100% confident although (that's why Option d is false).

This interval does not give us information about the sampling distribution (option e is false).

8 0
3 years ago
Simplify the following by combing like terms.
GREYUIT [131]
B. 3M-2N
this is because when you combine 4n and -6n you get -2n
5 0
3 years ago
Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima
Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416

3 0
3 years ago
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