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3 years ago

Help with these, if theyre right, ill give brainliest

Mathematics

2 answers:

adelina 88 [10]3 years ago

3 0

Answer:

q1: yes

q2: no

Step-by-step explanation:

2(5)+10(1)=20

10+10=20

20=20

(5)+(1)=6

5+1=6

6=6

(8)=(1)+3

8=1+3

8=4

gregori [183]3 years ago

3 0

Answer is q1. yes q2. no

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Write the mixed number as a percent 2 41/50

ehidna [41]

Answer:

∴ 2 $\frac{41}{50}$ = 282 %

Step-by-step explanation:

2 $\frac{41}{50}$

= [( 2 × 50) + 41] ÷ 50

= ( 100 + 41) ÷ 50

= $\frac{141}{50}$

=( $\frac{141 }{50}$ ) × $\frac{2}{2}$

= $\frac{282}{100}$

= 282 %

∴ 2 $\frac{41}{50}$ = 282 %

7 0

3 years ago

Read 2 more answers

Algebra find the unknown digit to make each statement true 2.48>2.4 1>2.463

valentina_108 [34]

We have 2.48>2.4 1>2.463. If we insert a '7' between that 4 and 1, we get:

2.48 > 2.471 >2.463, and this is true.

8 0

3 years ago

(Look at screenshot)

True [87]

Clear shown in graph

H(0)=5

At. no where graph passes through origin so y intercept is not 0 at anywhere

Domain is x values

Domain =[0,oo)

Range is y values set

Range=[5,50]

8 0

2 years ago

Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c

slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 16.000

Sample mean, $\bar{x}$ = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338$

Thus, the value of test statistic is 1.338

4 0

4 years ago

What is m∠FAD? 48° 42° 52° 38°

kirill [66]

Looks like 52° to me

4 0

3 years ago