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Otrada [13]
3 years ago
11

What is the y intercept of y=9x-11

Mathematics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

-11

Step-by-step explanation:

To find the y-intercept, simply look at the constant at the end of this equation. Let's look at the linear function equation. The equation is y=mx+b. In this case, the constant is b. The constant always is the non-x term, so for the question, the y-intercept would be -11.

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The function f(x) = (x - 4)(x - 2) is shown.
agasfer [191]

Answer:

all real numbers greater than or equal to -1

Step-by-step explanation:

In order to solve this problem we need to know the vertex and the direction its pointing.

First we expand,

x^2-6x+8

To find the x value of the vertex we use this formula (-b/2a).

-(-6)/2(1) = 3

Now we plug 3 in the equation to get the y value,

(3)^2 - 6(3) + 8 = 9 - 18 + 8 = -1

The vertex is (3,-1)

We know the graph points up because x^2 is positive

The vertex is the lowest point, so we now know that -1 is the starting range and if the graph is pointing up, that means all values greater than -1.

This leads to our answer all real numbers greater than or equal to -1.

6 0
3 years ago
Find the slope of the line that passes through the points (0, 6) and (20, 14).
mihalych1998 [28]

Answer:

2/5

Step-by-step explanation:

4 0
3 years ago
Can someone pls help me find the area of this please
Tamiku [17]

12.56

Step-by-step explanation:

A = π x r^2

r =2

2^2 = 4

π × 4 = 12.56

7 0
3 years ago
8) The height of a stack of CD cases is Proportional to the number of CD’s in the stack. A stack of 6 CD’s is 66mm high.* Find t
motikmotik

Step-by-step explanation:

well, when 6 CD cases are 66 mm high, then 1 CD case is 66/6 = 11 mm high.

a)

therefore, 10 CD cases are 11×10 = 110 mm high.

b)

y = 11x

3 0
2 years ago
A farmer took 2/3 of the strawberries that he harvested to a market. At the market, the farmer sold 1/4
Aliun [14]

Answer: If you are wondering how much he has left, there are 4/25 strawberries left

Step-by-step explanation:

5 0
3 years ago
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