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4 years ago

Solve for w . =−40−w6 Simplify your answer as much as possible.

Mathematics

1 answer:

Basile [38]4 years ago

7 0

Assuming that the left side of the equation is equal to zero, w=6.667

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Which inequality has -25 in its solution set?

Anastaziya [24]

Answer:

The answer is Y+20> -30

Step-by-step explanation:

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3 years ago

Elena knows dad 5 servings and granola has 1750 calories how many calories are in one serving of granola

aalyn [17]

If you have information about 5 servings, assuming that all servings have the same calories, the information about one serving is simply obtained by dividing the total by 5.

So, each serving has

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4 years ago

What is the sign of the product of two negative numbers?<br><br><br><br> Help!!

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Step-by-step explanation:

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3 years ago

- A store lowered all prices by 10%. By how

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3 years ago

Read 2 more answers

Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As

kakasveta [241]

Answer:

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that $\mu = 13.4224$

Find the probability that in a day, there will be at least 1 birth.

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985
$

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

7 0

3 years ago