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Volgvan
3 years ago
6

Jaden bought extra chicken because they’re on sale he wants to store them in the freezer which is such a -2°F he decided to turn

the freezer down to another 5° to be sure they don’t spoil
Mathematics
1 answer:
Maslowich3 years ago
8 0

Answer:

-2 - 5

-(2+5)

=7

Answer: -7 °F

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Need help on this math problem​
erik [133]

Answer:

-5, 18, \sqrt{13}

Step-by-step explanation:

We can solve the first equation, f of -3. The value of the function f is \frac{1+x^2}{x+1}, and plugging in -3 gets us \frac{1+9}{1-3}, this results in 10 divided by negative 2, which is negative 5.

Now, we must solve g of negative one third. The function g is defined as |9x-15|. Plugging in negative one third into the question gets us |9(-\frac{1}{3})-15|

9 times negative one third is -3, and -3 minus 15 is -18. The absolute value of -18 is 18.

Now, we must solve h of negative 2, and h is defined as \sqrt{-3-8x}. Plugging in negative 2, we have \sqrt{-3-8(-2)}. Negative 8 times negative 2 is positive 16, and 16 minus 3 is 13. The answer is the square root of 13

7 0
3 years ago
A garden measuring 12 meters by 6 meters is going to have a walkway constructed all around the perimeter, increasing the total a
damaskus [11]

Answer:

x=2

Step-by-step explanation:

Original width = 6

New width 6+x+x

Orignal length 12

New length  12+x+x

A = l*w

160 = ( 6+2x) ( 12+2x)

Factor

160 = 2( 3+x) 2(6+x)

Divide each side by 4

40 = (3+x) (6+x)

FOIL

40 = 18+ 6x+3x+ x^2

40 = 18 +9x+x^2

Subtract 40 from each side

0 = x^2 +9x -22

Factor

0 = (x +11) (x-2)

Using the zero product property

x +11 =0   x-2 =0

x= -11   x=2

Since we cannot have a negative  sidewalk

x =2

4 0
3 years ago
Read 2 more answers
The table
Lady_Fox [76]
Can you show a picture of the table please
4 0
3 years ago
URGENT HELP NEED!!! I WILL REWARD LOTS OF POINTS FOR THIS QUESTION!!! ANY IRRALEVENT OR SILLY QUESTION WILL BE INSTANTLY REPORTE
Ipatiy [6.2K]

Let the points be A,B,C

  • A(0,0)
  • B(24,16)
  • C(8,20)

#A

\\ \bull\sf\leadsto AB=\sqrt{(24-0)^2+(16-0)^2}=\sqrt{24^2-16^2}=\sqrt{576-256}=\sqrt{320}=17.4units(leg3)

\\ \bull\sf\leadsto AC=\sqrt{(8-0)^2+(20-0)^2}=\sqrt{8^2+20^2}=\sqrt{64+400}=\sqrt{464}=21.4units(leg1)

\\ \bull\sf\leadsto BC=\sqrt{(24-8)^2+(26-20)^2}=\sqrt{16^2+(-4)^2}=\sqrt{256+16}=\sqrt{272}=16.4units(leg2)

#B

We have to find perimeter

\\ \bull\sf\leadsto Perimeter=AB+AC+BC

\\ \bull\sf\leadsto Periemter=17.4+16.4+21.4

\\ \bull\sf\leadsto Perimeter=55.2units

#C

The length of leg3=17.4units

5 0
3 years ago
Read 2 more answers
Yo plz help me I don’t know this<br><br> Which number line shows the solution to -6 - (-4)?
Airida [17]

Answer:

B

Step-by-step explanation:

To solve -6-(-4) you need to break it down.

First, multiply -(-4) which would equal 4 (negative times negative equals positive)

Then add 4 to -6 (-6+4)

This equation is being expressed through option B

Hope this helps! :)

3 0
3 years ago
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