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4 years ago

5

I NEED HELP ASAPP PLEASE THIS IS DUE FOR SCHOOL PLEASE HELP ASAP and I don't have a calculator at home so I can't do this 2{3+10

/2+62-(4+2)}

1 answer:

coldgirl [10]4 years ago

6 0

Answer:

128

Step-by-step explanation:

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Please help me with this question

LUCKY_DIMON [66]

All I can find on this is that it would be 10/16 but thats not an awnser. hmmm

7 0

4 years ago

Given the following diagram, find the required measure.

Zielflug [23.3K]

Answer:

∠ 5 = 40°

Step-by-step explanation:

∠ 1 and ∠ 2 are adjacent angles and supplementary, thus

∠ 2 = 180° - ∠ 1 = 180° - 140° = 40°

∠ 5 and ∠ 2 are alternate angles and congruent , thus

∠ 5 = 40°

3 0

4 years ago

Azul spun a tri-color spinner twice. What is the probability that the spinner landed on the colors blue and green in any order?

guapka [62]

Answer:

The Probability that the spinner landed on the colors blue and green in any order = 2/9

Step-by-step explanation:

Given - Azul spun a tri-color spinner twice.

To find - What is the probability that the spinner landed on the colors blue and green in any order?

Solution -

Given that,

A tri-color spinner spun twice

So,

The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}

⇒n(S) = 9

Now,

Let A be an event that the spinner landed on the colors blue and green

So,

A = {BG, GB}

⇒n(A) = 2

Now,

Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)

= 2 ÷ 9

∴ we get

The Probability that the spinner landed on the colors blue and green in any order = 2/9

8 0

4 years ago

Please help me asap<br> Given the triangles are similar, find x.

Nadusha1986 [10]

Answer:

Uy

Step-by-step explanation:

7 0

3 years ago

Consider independent simple random samples that are taken to test the difference between the means of two populations. The varia

Arturiano [62]

Answer:

d. t distribution with df = 80

Step-by-step explanation:

Assuming this problem:

Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:

a. t distribution with df = 82.

b. t distribution with df = 81.

c. t distribution with df = 41.

d. t distribution with df = 80

Solution to the problem

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

So on this case the degrees of freedom are given by:

$df= 37+45-2=80$

And the best answer is:

d. t distribution with df = 80

5 0

3 years ago