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3 years ago

Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Mathematics

1 answer:

klio [65]3 years ago

3 0

Answer:

1. Understand your problem

2. Gather your resources

3. Come to an answer

4. Check your answer and present the solution

Step-by-step explanation:

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3 years ago

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To be able to do the problem 5(10 + 4) mentally, Zack does 50 + 20 instead of 5(14).

Eddi Din [679]

Answer:

1. Distributive

Step-by-step explanation:

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PLEASEEE HELP What is the solution to the equation represented by the model below?

Sauron [17]

Answer:

C) x=2

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Pleaseeeeeeeee help me :)

Korolek [52]

Answer:

f(x) = 5 - x has a negative slope.

Step-by-step explanation:

Y = mx + c is the general form for a straight line.

Whem m is negative the slope is negative

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3 years ago

Which of the following describes the domain of y = tan x, where n is any integer? A.x≠2nπ B. x≠π/2+nπ C. x≠nπ D.x≠nπ/2

lidiya [134]

$\bf tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}$

therefore, that fraction will become undefined if the denominator ever turns to 0.

now, recall that cos(π/2) is 0, and cos(3π/2) is 0, and cos(5π/2) is also zero and so on, thus

$\bf tan\left( \frac{\pi }{2} \right)=\cfrac{sin\left( \frac{\pi }{2} \right)}{cos\left( \frac{\pi }{2} \right)}\implies tan\left( \frac{\pi }{2} \right)=\cfrac{sin\left( \frac{\pi }{2} \right)}{0}
\\\\\\
tan\left( \frac{3\pi }{2} \right)=\cfrac{sin\left( \frac{3\pi }{2} \right)}{cos\left( \frac{3\pi }{2} \right)}\implies tan\left( \frac{3\pi }{2} \right)=\cfrac{sin\left( \frac{3\pi }{2} \right)}{0}
$

$\bf tan\left( \frac{5\pi }{2} \right)=\cfrac{sin\left( \frac{5\pi }{2} \right)}{cos\left( \frac{5\pi }{2} \right)}\implies tan\left( \frac{5\pi }{2} \right)=\cfrac{sin\left( \frac{5\pi }{2} \right)}{0}
\\\\\\
tan\left( \frac{7\pi }{2} \right)=\cfrac{sin\left( \frac{7\pi }{2} \right)}{cos\left( \frac{7\pi }{2} \right)}\implies tan\left( \frac{7\pi }{2} \right)=\cfrac{sin\left( \frac{7\pi }{2} \right)}{0}$

$\bf tan\left( \frac{\pi }{2}+\pi \right)=\cfrac{sin\left( \frac{\pi }{2}+\pi \right)}{cos\left( \frac{\pi }{2}+\pi \right)}\implies tan\left( \frac{\pi }{2}+\pi \right)=\cfrac{sin\left( \frac{\pi }{2}+\pi \right)}{0}
\\\\\\
domain\implies \{x|x\in \mathbb{R}, ~~x\ne \frac{\pi }{2}+n\pi,~~n\in \mathbb{Z} \}$

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3 years ago