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NemiM [27]
2 years ago
11

Hellllllllllllllllllllllllllllp!!!!!!!!!!!!!!!! will give brainliest

Mathematics
2 answers:
zavuch27 [327]2 years ago
5 0

Answer:

Step-by-step explanation:

3in/4 = 0.75in(Diameter) for each circle

r = 0.375

A = πr^2

A(for 1 circle) = 0.141π

A(for 1/4 circle) = 0.035π

A x 4 because we have 4 circles =

0.141π

0.141π(area of middle) + 0.141π(area of circle) =

0.282π or 0.886in^2

AnnyKZ [126]2 years ago
4 0

Answer:

I have no idea cause I cant see the words the well-

Step-by-step explanation:

sorry-

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130 degrees

Step-by-step explanation:

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3 years ago
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100%=1.0 hope this helps
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(look at image) can i get help with these two?
serg [7]

Answer:

1. x = 2, AC = 30, AB - 4

2. y = 4, AB = 34, BC = 34

Step-by-step explanation:

1. AB + BC = AC so 26 + (10 - 3x) = 14x +2 and then add 3x to both sides and subtract 2 from both sides to get x on one side and an integer on the other side which is 34 = 17x and then divide 17 from both sides to get x = 2 and then substitute x into the AC and AB equations to find the values its equal to.

2. The symbol in the given means that the two lengths are congruent which means they are equal to each other so you put the two equations equal to each other and solve for y. 9y -2 = 14 + 5y, so subtract 5y from both sides and add two to both sides to get 4y = 16 and then divide both sides by 4 to get y = 4 and then substitute in the answer to find the lengths of AB and BC.

6 0
3 years ago
A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery servic
sineoko [7]

Answer:

55.32% probability that a late package was delivered by express delivery service 2

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Late delivery.

Event B: Service 2 was used.

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100 - 35 = 65%.

So P(B) = 0.65

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35% from service 1. Of those, 3% are late.

65% from service 2. Of those, 2% are late.

So

P(A) = 0.35*0.03 + 0.65*0.02 = 0.0235

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P(B|A) = \frac{0.65*0.02}{0.0235} = 0.5532

55.32% probability that a late package was delivered by express delivery service 2

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egoroff_w [7]
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