Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Y=11x/20 +.25
<span>Solve for </span><span>y</span><span> by </span>simplifying<span> both sides of the </span>equation<span>, then isolating the </span>variable<span>.</span>
Answer:
45 cubic units
Step-by-step explanation:
Vtotal = 1/2 (2.5*3) * 6 *2
where
2.5 is the base
3 is the height
6 is the length
2 is the number of prisms
