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fredd [130]
3 years ago
10

Jen picked 3/4 of a gallon of strawberries in half an hour. If she keeps picking strawberries at the same rate, how many gallons

will she have picked in 2 hours.
Mathematics
1 answer:
Ratling [72]3 years ago
6 0
Hello!

3/4 = 0.75 as a decimal

We know that Jen picks 0.75 of a gallon of strawberries in half an hour, and now we want to find out how many gallons she'll pick in 2 hours.

Half an hour = 0.5 2 ÷ 0.5 = 4 There are four half hours in 2 hours.

0.75 × 4 = 3

ANSWER:

Jen will have picked 3 gallons of strawberries in 2 hours.
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write equation that has base of 3 stretched vertically by factor of 2/3 reflected in y axis, asymptote of y=2 and passes through
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The exponential equation is y = \frac23(3)^{-x+0.74} + 2

<h3>How to determine the equation?</h3>

An exponential function is represented as:

y = b^x

The base is 3.

So, we have:

y = 3^x

It is stretched vertically by 2/3.

So, we have:

y = \frac23(3)^x

When reflected over the y-axis, we have:

y = \frac23(3)^{-x}

An asymptote of y = 2, makes the function becomes

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Lastly, it passes through the point (0, 3.5).

So, we have:

y = \frac23(3)^{-x+h} + 2

This gives

3.5 = \frac23(3)^{-0+h} + 2

3.5 = \frac23(3)^{h} + 2

Subtract 2 from both sides

1.5 = \frac23(3)^{h}

Multiply by 3/2

2.25 = (3)^{h}

Take the logarithm of both sides

log(2.25) = h * log(3)

Solve for h

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Substitute h = 0.74 in y = \frac23(3)^{-x+h} + 2

y = \frac23(3)^{-x+0.74} + 2

Hence, the exponential equation is y = \frac23(3)^{-x+0.74} + 2

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