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2 years ago

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Mathematics

1 answer:

Lostsunrise [7]2 years ago

3 0

start with elimination. 8 x 8 is only 64 so C and D dont make sense. The are of the circle is pi(r)². so the radius is 4 squared then multiply by pi and devide by 5 to get the 5 equal parts. So B 10.

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The flower color of bigleaf hydrangeas is determined by the soil's pH. A gardener growing blue hydrangeas believes that lime may

barxatty [35]

PH is calculated by the negative logarithm of the hydrogen concentration in a solution. Therefore, the pH in this case is:

pH = -log (0.0000006)
pH = 6.22

Therefore the correct answer among the choices is the last option, pH of 6 with a color pink.

8 0

3 years ago

A manufacturer of industrial solvent guarantees its customers that each drum of solvent they ship out contains at least 100 lbs

Hitman42 [59]

Answer:

Step-by-step explanation:

Let X be the solvent present

Then given that the manufacturer of industrial solvent guarantees its customers that each drum of solvent they ship out contains at least 100 lbs of solvent.

X is N(101.3, 3.68)

a) $P(X>100) = P(Z>\frac{100-101.3}{3.68} =P(Z>-0.35)\\=0.6368$

Probability = 0.6368

b) $P(X>100)= 0.97$ means Z score = 1.88

X=100+1.88(s) =101.3

s=1.3/1.88=0.6914

4 0

3 years ago

For what values of a is the value of the binomial 2a−1 smaller than the value of the binomial 7−1.2a by 7?

Nimfa-mama [501]

ANSWER

$a = \frac{5}{16}$

EXPLANATION

We want to find the value of a for which the binomial, 2a-1 is smaller than the value of the binomial 7-1.2a by 7.

This means that, when we subtract 2a-1 from 7-1.2a, we should get 7.

$7 - 1.2a - (2a - 1) = 7$

Expand:

$7 - 1.2a - 2a + 1= 7$

Group similar terms:

$- 1.2a - 2a = 7 - 7 - 1$

$- 3.2a = - 1$

Divide both sides by -3.2,

$a = \frac{ - 1}{ - 3.2}$

$a = \frac{5}{16}$

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3 years ago

Question 3<br> Find the constant of variation (k).<br><br> -y + 9x = 0

egoroff_w [7]

Answer:

Step-by-step explanation:

-y + 9x = 0

y = 9x

y = kx

k = 9

3 0

3 years ago

Consider the function f(x)= 1-|x-1|+|x+1| for -3<x<3. Recall that the absolute function can be represented as a piece wise

Kruka [31]

By the definition for the absolute value,

$|x-1|=\begin{cases}x-1&\text{for }x\ge1\\-(x-1)&\text{for }x$
$|x+1|=\begin{cases}x+1&\text{for }x\ge-1\\-(x+1)&\text{for }x$

So for the compound function $f(x)=1-|x-1|+|x+1|$ , there are three intervals to consider. What happens when $x$ ? when $-1\le x$ ? when $x\ge1$ ?

You have

$f(x)=\begin{cases}1-(-(x-1))+(-(x+1))=-1&\text{for }x$

8 0

3 years ago

Help on this question​

Help on this question