All categories

3 years ago

Help on this question

Mathematics

1 answer:

Lostsunrise [7]3 years ago

3 0

start with elimination. 8 x 8 is only 64 so C and D dont make sense. The are of the circle is pi(r)². so the radius is 4 squared then multiply by pi and devide by 5 to get the 5 equal parts. So B 10.

You might be interested in

Why do whole numbers raised to an exponent get greater well fractions raised to an exponent get smaller

adelina 88 [10]

Because when you raise an exponent on a fraction, it is basically dividing into itself. Imagine 1/3 multiplied my 3 (Ans is 1), the fractions aren't whole numbers so when they multiply into another number, it uses division

4 0

3 years ago

In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre

Veseljchak [2.6K]

Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that $p = 0.09$

41 people arrested for DUI in Illinois are selected at random.

This means that $n = 41$

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158$

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ .

Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791$

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

$E(X) = np = 41*0.09 = 3.69$

d. What is the standard deviation of the number of repeat offenders?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83$

4 0

3 years ago

Hello I need someone to help me answer 10 algebra 1 math test questions i will pay money after or give brainiest on each questio

shtirl [24]

Hello! i’m in algebra 2 and passed algebra 1 with a 97%. any chance i might be able to help you? i don’t want money for it tho

6 0

3 years ago

A drawer contains 4 red socks, 5 white socks, and 6 blue socks. Without looking, you draw out a sock and then draw out a second

mezya [45]

The probability is (4/16) * (10/16) = 5/32

6 0

3 years ago

Part A:

shusha [124]

Part A:

Six Tents Holds 42 People

Nine Tents Holds 63 People

10 Tents Holds 70 People

Part B:

Number of tents|||Number of people

1 |||7

6 |||42

9 |||63

10 |||70

Part C:

Tents=x

1x=7 people

8 0

3 years ago

Read 2 more answers

Help on this question​

Help on this question