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3 years ago

6

Molly was packing goody bags for her birthday party. She has 64 jolly ranchers and 56 lollipops. What is the greatest number of

bags that she can make if she wants the same number of each candy in each bag?

1 answer:

Ede4ka [16]3 years ago

7 0

Answer 8 kids, 8 jolly ranchers each, 7 lolipops each

Step-by-step explanation:

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What are the domain and range of the exponential function below? <br><br> <img src="https://tex.z-dn.net/?f=F%28x%29%20%3D%205%5

faust18 [17]

Answer:

B

Step-by-step explanation:

The domain is the set of x values for which the function is defined.

The range is the set of y values for which the function is defined.

Attached is the graph of the exponential function.

It is the basic graph of exponential function of y = 5^x which is shifted 6 units above (because of +6 at the end).

<em><u>Looking at the graph, the domain is the set of all x values.</u></em>

<em><u>The range is anything above 6.</u></em>

Correct answer is B.

3 0

3 years ago

I have nooooo clue, please help

Aleksandr-060686 [28]

Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

case d) $y^{2}=6x$ ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

so

$y=(1/3)x^{2}$

$a=(1/3)$

so

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

so

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

so

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

so

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

3 0

3 years ago

Is the point (4,2) the solution to the system? Why or why not? Explain your reasoning.

VMariaS [17]

Solve the top equation to get on variable on one side
2x-y=6
-y=-2x+6
y=2x-6
then plug in the coordinate for x and y for both equations. if both equations are true then it’s a solution
2=2(2)+6
2=10

4+2=6

so it’s not a solution

4 0

3 years ago

Law of cosines <br><br> HELP MES

Lorico [155]

Answer:

70.52 degrees

Step-by-step explanation:

To find the angles, we must first find the lengths of each side of the triangle. Adding up the respective radii, we can see that

XY = 5+4 = 9 CM

XZ = 6+5 = 11 CM

ZY = 4+6 = 10 CM

Now we can apply the cosine rule

$C\:=\:\sqrt{A^2+B^2-2ABcosx}$

We need to rearrange the rule to solve for x, our missing angle

$x\:=\:cos^{-1}\left(\frac{a^2+b^2-c^2}{2ab}\right)$

solving for our unknown angle:

$x\:=\:cos^{-1}\left(\frac{9^2+10^2-11^2}{2\cdot 9\cdot 10}\right)$

$x\:=\:70.52^{\circ }$

Therefore angle YXZ is 70.52 degrees

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3 years ago

A girl 1.54m girl, is 30m away from tower whose height is 53.5m. determine the angel of angle of elevation from her eye to the t

steposvetlana [31]

Answer:

reference attached

Step-by-step explanation:

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2 years ago

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