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3 years ago

Find the length of a diagonal of a square with sides of 14 feet long. [?][feet /

Mathematics

1 answer:

inessss [21]3 years ago

4 0

Answer:

14√2 feet

Step-by-step explanation:

The length of a diagonal of a square is $L=S\sqrt{2}$ where $S$ is the side length of the square. Therefore, $L=14\sqrt{2}$ .

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At an ocean depth of 20 m, a buoy bobs up and then down 2 m from the ocean's depth. Four seconds pass from when the buoy is at i

rusak2 [61]

Well 10x2 is 20 so 10 is your answer hope this helps

3 0

4 years ago

What is the length of segment AB to the nearest tenth?

ankoles [38]

Answer:

4.9 units

Step-by-step explanation:

Distance between 2 points= sqrt [(x-x)^2 + (y-y)^2

A= -4,2) and B= (1,4)

d = sqrt[(-4-1)^2 + (2-4)^2]

= sqrt (25+4)

= sqrt29

= 4.9 units

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3 years ago

Solve for A<br><br> Thank u so much !

lianna [129]

Answer:

$\huge\boxed{A=4d^2+4h}$

Step-by-step explanation:

$\dfrac{1}{4}A-h=d^2\qquad\text{add}\ h\ \text{to both sides}\\\\\dfrac{1}{4}A-h+h=d^2+h\\\\\dfrac{1}{4}A=d^2+h\qquad\text{multiply both sides by 4}\\\\4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1}A=4d^2+4h\\\\A=4d^2+4h$

6 0

3 years ago

Read 2 more answers

Phythagorean theorem help me plsss

marysya [2.9K]

Answer:

Step-by-step explanation:

We know that a^2+b^2=c^2 from the Pythagorean theorem where a and b are the legs and c is the hypotenuse

4^2+3^2 = c^2

16+9 = c^2

25 = c^2

Taking the square root of each side

sqrt(25) = sqrt(c^2)

5 =c

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3 years ago

Read 2 more answers

I really need help, it won't take long to solve (:

stira [4]

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48. xy = 0
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D

49. Plug in each of the answer choices to see if they work.
B

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3 years ago