-10. One type of system of equations that results in infinite solutions is one where both sides of the equation are exactly equal. Here, setting the second equation equal to -10 becomes 2y - 4x = -10. This can be rearranged into 2y = 4x - 10. Dividing everything by 2 results in y = 2x - 5, which is exactly what the first equation is. Substituting one equation into another, we get 2x - 5 = 2x - 5, which is a true statement for all values of x.
Answer:
x = 7
y = 3
z (max) = 4950/3 = 1650
Step-by-step explanation:
Let call
x numbers of church goup and
y numbers of Union Local
Then
First contraint
2*x + 2*y ≤ 20
Second one
1*x + 3*y ≤ 16
Objective Function
z = 150*x + 200*y
Then the system is
z = 150*x + 200*y To maximize
Subject to:
2*x + 2*y ≤ 20
1*x + 3*y ≤ 16
x ≥ 0 y ≥ 0
We will solve by using the Simplex method
z - 150 *x - 200*y = 0
2*x + 2*y + s₁ = 20
1*x + 3*y + 0s₁ + s₂ = 16
First Table
z x y s₁ s₂ Cte
1 -150 -200 0 0 = 0
0 2 2 1 0 = 20
0 1 3 0 1 = 16
First iteration:
Column pivot ( y column ) row pivot (third row) pivot 3
Second table
z x y s₁ s₂ Cte
1 -250/3 0 0 200/3 = 3200/3
0 - 4/3 0 -1 2/3 = -20/3
0 1/3 1 0 1/3 = -20/3
Second iteration:
Column pivot ( x column ) row pivot (second row) pivot -4/3
Third table
z x y s₁ s₂ Cte
1 0 0 750/12 700/6 = 4950/3
0 1 0 3/4 -1/2 = 7
0 0 1 -1/4 1/2 = 9/3
7x+5y=-24 (1)
4x+y=42 (2)
multiply equation (2) by 5 to get
20x+5y=210 (3)
then calculate (3)-(2) which gives you
13x=234 hence x=18
then substitute for x in either equation to get y=-30
Answer:
See below
Step-by-step explanation:
the common ratio, r <1 so it CONVERGES (r = 1/2 in this series)
sum = a1 ( 1-r^n) / (1-r) = 1000(1-.5^10)/(1-1/2) = ~1998
for n= 30 this results in ~~2000
As it continues, the terms get smaller and smaller and the SUM converges on 2000.
