We are trying to find the average speed of the plane, which is mph, or
. Using proportions, we can find the average speed of the plane in mph:
![\dfrac{525 \,\, \textrm{miles}}{1.75 \,\,\textrm{hours}} = \dfrac{x \,\, \textrm{miles}}{1 \,\,\textrm{hour}}](https://tex.z-dn.net/?f=%5Cdfrac%7B525%20%5C%2C%5C%2C%20%5Ctextrm%7Bmiles%7D%7D%7B1.75%20%5C%2C%5C%2C%5Ctextrm%7Bhours%7D%7D%20%3D%20%5Cdfrac%7Bx%20%5C%2C%5C%2C%20%5Ctextrm%7Bmiles%7D%7D%7B1%20%5C%2C%5C%2C%5Ctextrm%7Bhour%7D%7D)
- Use the information from the problem to create a proportion. Remember that we are looking for mph, so we will call that
.
![\dfrac{525}{1.75} \,\textrm{miles} = x \,\textrm{miles}](https://tex.z-dn.net/?f=%5Cdfrac%7B525%7D%7B1.75%7D%20%5C%2C%5Ctextrm%7Bmiles%7D%20%3D%20x%20%5C%2C%5Ctextrm%7Bmiles%7D)
- Multiply the entire equation by
![1 \,\textrm{hour}](https://tex.z-dn.net/?f=1%20%5C%2C%5Ctextrm%7Bhour%7D)
![\dfrac{525}{1.75} = 300 = x](https://tex.z-dn.net/?f=%5Cdfrac%7B525%7D%7B1.75%7D%20%3D%20300%20%3D%20x)
- Divide both sides of the equation by
to clear both sides of the mile unit
The average speed of the plane is 300 mph.
Answer:
b=(-10-a)/4
First factor out the common number:3
Then divide both sides by 3
Then simplify 30/3 to 10
Then subtract a to get your answer
X^2-5x-14
It is the correct answer I think
First solve the length of side BC, CD, EF and FA
Since BC = CD = sqrt( 10^2 + 10^2)
BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2)
= 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607
= 93
The area is made up be triangle FAE, rectangle ABDE and
triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>