M∠ADB + m∠BDC = m∠ADC [<span>angle addition postulate]
x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25
a
m</span>∠ADB = x = 25°
b
m∠BDC = x + 10 = 25 + 10 = 35°
It has to be C- addition and subtraction signs.
20 rows * 15 seats per row=300 seats in section J
300 seat in Section J * $18 per ticket= $5,400 in revenue
1) Line should be parallel to y = 3x+6, so slope of this line should be =3.
y=mx +b
y=3x +b
Now we have to find b (y-intercept), using the point (-10, 2.5).
2.5 = 3*(-10)+b
b=2.5+30=32.5
y=3x + 32.5
2) The line should be perpendicular to y = -4x -2, so its slope is going to be negative reciprocal m= 1/4.
Now we have to find b (y-intercept), using the point (-16, -11).
y=(1/4)x +b
-11=(1/4)*(-16) + b
-11 = -4 +b
b = -7
y=(1/4)x - 7
680/96
= 7.1
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