Write each vector as a linear combination of the vectors in s. s = {(2, 0, 7), (2, 4, 5), (2, −12, 13)} (a) u = (−1, 7, −7)
Paladinen [302]
The vectors in s are linearly dependent, but you can make u from
.. (2, 4, 5)/16 -9*(2, -12, 13)/16 = (-1, 7, -7)
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
1) Taking in account that the function is f(x)= -(2/3) |x+4|-6, I enclose a file with the graph.
That helps you to conclude:
a) The graph of f(x) has a vertex on (-4, -6)
b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.
c) The graph of f(x) opens downward
d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)
Answer: the graph of f(x) is horizontally stretched.
Answer:
there are 0 solutions to the equation
Step-by-step explanation:
To know how many solutions are in the problem, we have to solve for x and see what result we have left. According to the result, we will know how many solutions there are
8x + 47 = 8(x + 5)
8x + 47 = 8*x + 8*5
8x + 47 = 8x + 40
8x - 8x = 40 - 47
0 = -7
As we can see we are left with an equality that is not fulfilled, this means that there is no solution to the problem, at least in the field of real numbers