Which statement is true about f(x)-2/3lx+4l-6?
2 answers:
1) Taking in account that the function is f(x)= -(2/3) |x+4|-6, I enclose a file with the graph.
That helps you to conclude:
a) The graph of f(x) has a vertex on (-4, -6)
b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.
c) The graph of f(x) opens downward
d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)
Answer: the graph of f(x) is horizontally stretched.
That helps you to conclude:
a) The graph of f(x) has a vertex on (-4, -6)
b) When you multiply a function times 2/3 it is vertically compressed which is equivalent to horizontally streched.
c) The graph of f(x) opens downward
d) The domain of f(x) is all the real values (the absolute function accepts any value of x either positive or negative)
Answer: the graph of f(x) is horizontally stretched.
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Answer:
vertex = (- 7, - 87)
Step-by-step explanation:
given a parabola in standard form : ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
p² + 14p - 38 is in standard form
with a = 1, b = 14, c = - 38, hence
= -
= -7
substitute x = - 7 into the equation for corresponding value of y
y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87
vertex = (- 7, - 87)