Standard form equation of hyperbola is:
y² / a² + x² / b² = 1
Vertices are: ( 0, a ) and ( 0, - a ) so : a = 10
Asymptotes are : y = +/- a/b x
a/b = 5/6
10/b = 5/6
5 b = 60
b = 60 : 5
b = 12
Answer:
y² / 100 + x² / 144 = 1
Part A? Is that what you need?
A <em>difference of squares</em> is exactly what it suggests - the difference between two perfect squares. 25 - 9, 4 - 1, x² - 25, and 125 - b² are just a few examples. Differences of squares factor very nicely, too. For any difference of squares x² - y²:
x² - y² = (x + y)(x - y)
We can see that this is true by taking the right side of the equation and distributing:
(x + y)(x - y) = (x + y) · x + (x + y) · (-y) = x² + xy - xy - y² = x² - y²
We notice in our given expression that 36 is a perfect square - namely, 6². We want the expression x² + ?x - 36 to look like x² - 6², which we can accomplish if we replace the question mark with a 0.
Answer:
E
Step-by-step explanation:
I have never heard of it in my entire life.
Answer:
6.5y+10 or the second option
Step-by-step explanation:
0.5y+10.5+6.5y-0.5-0.5y
Combine like terms:
10.5-0.5 is 10
0.5y+6.5y-0.5y is 6.5y
So, it is 6.5y +10
second option.
Hope this helps! You can hit the crown if you want.
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