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3 years ago

Where should the x be????

Mathematics

1 answer:

Eduardwww [97]3 years ago

7 0

There should be an X over 9.6, 0, √16, and 2.45.

9.6 = Integer
0 = Whole Number
√16 (or 4) = Counting Numbers
2.45 = Integer

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3 years ago

What is 7 2/10 as a decimal

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4 years ago

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What is the first step in evaluating the expression 6−(4÷2×5)2?

OLEGan [10]

Answer:

Step-by-step explanation:

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3 years ago

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Please help!!! I’ll give you the Brainliest answer!! Thank you!!

dem82 [27]

Answer:

hi its C

Step-by-step explanation:

this question can be solved by thales law

$\frac{x}{5} = \frac{x - 6}{3} \\ \\ 3x = 5x - 30 \\ \\ 2x = 30 \\ x = 15$

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3 years ago

A quadratic equation is shown below: 3x2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining the

Triss [41]

Answer:

$\text{The roots of }3x^2+5x-8=0\text{ are }x=1,\frac{-8}{3}$

Step-by-step explanation:

$\text{Part A: Given a quadratic equation }3x^2-15x+20=0$

$\text{Comparing above equation with }ax^2+bx+c=0$

a=3, b=-15, c=20

Discriminant can be calculated as

$D=b^2-4ac$

$D=(-15)^2-4(3)(20)=225-240=-15$

The roots are imaginary

The solution is

$x=\frac{-b\pm\sqrt{D}}{2a}$

$x=\frac{-(-15)\pm \sqrt{-15}}{2(3)}=\frac{15\pm\sqrt{15}i}{6}$

The roots are not real i.e these are imaginary

$\text{Part B: Given a quadratic equation }3x^2+5x-8=0$

$\text{Comparing above equation with }ax^2+bx+c=0$

a=3, b=5, c=-8

Discriminant can be calculated as

$D=b^2-4ac$

$D=(5)^2-4(3)(-8)=25+96=121>0$

The roots are real

By quadratic formula method

The solution is

$x=\frac{-b\pm\sqrt{D}}{2a}$

$x=\frac{-5)\pm \sqrt{121}}{2(3)}=\frac{-5\pm 11}{6}$

$x=1,\frac{-8}{3}$

which are required roots.

I choose this method because I can get the solutions directly by substituting the values in formula, and I don't have to guess the possible solutions.

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3 years ago