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1 year ago

Question 6 of 10 Which choice is equivalent to the product below?

Mathematics

2 answers:

marshall27 [118]1 year ago

8 0

The answer is d because when you get the square root of 8*5 you get 6.32 and when you get the square root of 2 and ten you get the same

ohaa [14]1 year ago

6 0

Answer: D

Step-by-step explanation:

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Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1

Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in $\frac{1}{1.5}$ minutes

Hence

10.50 mph will be increased in $\frac{1}{1.5} \times 10.50$ minutes

$= \frac{10.5}{1.5}$

$=7$

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0

2 years ago

What is { y= 4x+10 and y= 3x+9

Musya8 [376]

Answer:

x=-1

Step-by-step explanation:

y=4x+10

y=3x+9

-----------

4x+10=3x+9

4x-3x=9-10

x=-1

5 0

2 years ago

Read 2 more answers

bonnie runs 1 2/3 times as far as john each day if bonnie runs 5 miles on monday 3 1/2 miles on tuesday and 5 3/4 miles on wedne

nignag [31]

Answer:

3 miles on Monday

2¹/₁₀ miles on Tuesday

3⁹/₂₀ miles on Wednesday

Step-by-step explanation:

We are told that Bonnie runs 1⅔ (⁵/₃) times as far as John each day

This means that John runs ³/₅ times as far as Bonnie.

MONDAY:

Bonnie runs 5 miles on Monday, therefore, John runs:

³/₅ * 5 = 3 miles

TUESDAY:

Bonnie runs 3½ (⁷/₂) miles on Tuesday, therefore, John runs:

³/₅ * ⁷/₂ = ²¹/₁₀ = 2¹/₁₀ miles

WEDNESDAY:

Bonnie runs 5³/₄ (²³/₄) miles on Wednesday, therefore, John runs:

³/₅ * ²³/₄ = ⁶⁹/₂₀ = 3⁹/₂₀ miles

6 0

2 years ago

6) (after 2.3) Consider the infinite system of linear equations in two variables given by ax + by = 0 where (a, b) moves along t

Paraphin [41]

Answer:

Step-by-step explanation:

Given infinite system of linear equations is ax + by = 0

when (a,b) moves along unit circle in plane.

a) system having unique system (0, 0)

Since two of equation in thus system will be

$1.x+0.y=0\\x=0$

and

$0.x+1.y=0\\y=0$

It is clear that x = 0, y= 0 is the only solution

b) Linear independent solution in this system gives some set of solutions

$1.x+0.y=0\\\x=0$

and

$0.x+1.y=0\\y=0$

Vector form is

$\left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =I$

c) for this equation if add 0x +0y = 0 to system , Nothing will change

Because [0,0] satisfies that equation

d) If one of the equation is ax + by = 0.00001

where 0.00001 is small positive number

so, the system will be inconsistent

Therefore, the system will have no solution.

6 0

2 years ago

Anybody help me please

GrogVix [38]

Answer:

Rotation 180° counterclockwise about the origin

7 0

2 years ago

Read 2 more answers