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3 years ago

What is the scientific notation of 0.000487

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

0.000487=4.87⋅10−4.............

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Help asappppp? i’m having trouble on wat the 1/4 point is

blagie [28]

Answer:

(-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

(x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

M = (A+B)/2

A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

(Q -A)/(B -A) = 1/4

4Q -4A = B -A . . . . cross multipliy

Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

Q = (3M -B)/2 . . . . reduce the fractions

Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0

3 years ago

Lots of 40 components each are deemed unacceptable if they contain 3 or more defectives. The procedure for sampling a lot is to

MrRissso [65]

Answer:

The probability of founding exactly one defective item in the sample is P=0.275.

The mean and variance of defective components in the sample are:

$\mu=0.375\\\\\sigma^2=0.347$

Step-by-step explanation:

In the case we have a lot with 3 defectives components, the proportion of defectives is:

$p=3/40=0.075$

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).

The probability of having one defective in the sample is:

$P(k=5)=\binom{5}{1}p^1(1-p)^4=5*0.075*0.925^4=0.275$

b) The mean and variance of defective components in the sample is:

$\mu=np=5*0.075=0.375\\\\\sigma^2=npq=5*0.075*0.925=0.347$

The Chebyschev's inequality established:

$P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}$

6 0

4 years ago

HELP ME GUYS

Tatiana [17]

Answer:

aida's work is the correct answer

7 0

2 years ago

Solve x2 − 10x = −13.

aev [14]

Answer:

Step-by-step explanation:

First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial $x^{2}-10x+13$ . We can now use the quadratic formula to solve.

Remember that the quadratic formula is

$\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

Substitute the numbers from the equation into the formula.

$\frac{-(-10)+/-\sqrt{(-10)^{2}-4(1)(13) } }{2(1)}$

Simplify:

$\frac{10+/-\sqrt{100-52} }{2}$

$\frac{10+/-\sqrt{48} }{2}$

Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with $5+/-\sqrt{48}$ .

Hope this helps!

6 0

3 years ago

If AB = 13, BC = 9, and CA = 17, list the angles in order from smallest to largest.

Licemer1 [7]

A,C,B
This is the answer;BC,AB,CA

8 0

4 years ago