3/10 is it because the greatest common factor is 2.
Answer:
0.6048
Step-by-step explanation:
Given the following :
Assume a normal distribution :
Mean (m) = 105
Standard deviation (sd) = 20
Find the probability that a randomly selected adult has an IQ between 88 and 122 .
Z = (x - m) / sd
For IQ score of 88:
Z = (88 - 105) / 20
Z = (-17) / 20
Z = - 0.85
For IQ score of 122:
Z = (122 - 105) / 20
Z = (17) / 20
Z = 0.85
P(-0.85<Z<0.85) = P(Z < 0.85) - P(Z < - 0.85)
P(-0.85<Z<0.85) = (0.8023 - 0.1977)
P(-0.85<Z<0.85) = 0.6048
Divide 4 on each side and X will be = to 5
4x/4 = 20/4
X = 5
<span>the answer is 7.6196875. </span>
