F(x) is a polynomial with real coefficients. Hence for any real numbers x, ...
• f(x) is a real-valued function
• f(x) is continuous on any closed interval of real numbers, such as [4, 6]
• f(x) is differentiable on any open interval of real numbers, such as (4, 6)
The conclusion is that there exists some "c" such that f'(c) = (f(6) -f(4)/(6 - 4).
The slope of interest is
m = (f(6) -f(4))/(6 -4) = (-44 -(-44))/2 = 0
The slope f'(x) is -20 +4x. It will be zero where
0 = -20 +4x
20 = 4x
5 = x
So, f'(5) = 0 = m
The point "c" of interest is
c = {5}
Answer: x = 12
Step-by-step explanation:
We know that the whole angle is 90°. Therefore, we can set up our equation like this:
90 = 50 + 3x + 4
Lets combine like terms:
90 = 54 + 3x
Now, let’s isolate the variable. To do this, we have to move 54 to the other side, making it negative.
90 - 54 = 3x
36 = 3x
Now, you divide, the leave the variable by itself.
=
Therefore, x = 12.
Answer:
Step-by-step explanation:
What are the possible answer choice(s)?
Proof by Contraposition.
Let me know if I was correct or horribly wrong.
ANSWER=30
because if you 8.2-2.3 you get 5.9 and if you divide by 177 it is 30
hope it helps