2 years ago

5<b-3. whats the answer????

Mathematics

2 answers:

9966 [12]2 years ago

8 0

Answer:

5<b-3

Add 3 on both sides

8<b

The variable will always go on the left side of the equation. To flip the equation, you must also flip the less than sign to a greater than sign.

b>8

Hope I helped!

viva [34]2 years ago

4 0

Answer:

8<b

Step-by-step explanation:

5<b-3

To isolate b, add 3 to each side

5+3<b-3+3

8<b

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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