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Lostsunrise [7]
3 years ago
10

If Alex feeds his turtle the same

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

14 times whatever you feed him

Step-by-step explanation:

if you feed him x food twice a day (2x) for 7 days (2x*7) you get 14x or 14 amt of the food being fed

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A baker needs 3/5 cup water for every 2/3 cup flour. Using this ratio, how much flour is needed for 1/3 cup water?
Llana [10]
<h3>Answer:  Choice A)  10/27 cup flour</h3>

=======================================================

Work Shown:

3/5 cup water = 2/3 cup flour

15*(3/5) cup water = 15*(2/3) cup flour

9 cups water = 10 cups flour

9/27 cup water = 10/27 cup flour

1/3 cup water = 10/27 cup flour

In the second step I multiplied both sides by 15 to clear out the fractions. In the second to last step, I divided both sides by 27 so that it forms the fraction 9/27 which reduces to 1/3.

5 0
3 years ago
What is the value of ?
Bess [88]

Answer:

Here is the solution....hope it helps:)

7 0
3 years ago
Jeremy is taking a photography class, but he doesn't own a camera. The class organizers will rent him a camera for $6 per day. J
Mazyrski [523]
Solving the given inequality for d, we get...

6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83

Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}

The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6

8 0
3 years ago
Read 2 more answers
If A= 30°verify:sin2A=2sinA.cosA​
vekshin1

Answer:

..........hope it helps.....

7 0
3 years ago
3/5 of the class were boys. The teacher divided the boys equally into groups so the each group of boys had 1/10 of the number of
Lana71 [14]
I think boys =18
          girls=12
boys :x
girls:y
student:z
the number of group for the boys :n
the numberof group for the girls :m
so x=(3/5)*z
    y=(2/5)* z
x/y=3/2
3y-2x=0
(1/10)*z*n=(3/5) *z
so n=6
(1/5)*z*m=(2/5)* z
put x=(1/10)*z*6
    y=(1/5)*z*2
 into 3y-2x=0 and z=30
 z=30 so x=(1/10)*30*6=18
               y=(1/5)*30*2=12


4 0
3 years ago
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